# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
94437 | Kastanda | Longest beautiful sequence (IZhO17_subsequence) | C++11 | 3 ms | 632 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
using namespace std;
const int N = 100005, SQ = 1024;
int n, ts, A[N], K[N], P[N], R[N];
pair < int , int > dp[SQ+1][SQ+1][11+1];
inline void MAX(pair < int , int > &a, pair < int , int > b)
{
a = max(a, b);
}
int main()
{
scanf("%d", &n);
for (int i = 1; i <= n; i++)
scanf("%d", &A[i]);
for (int i = 1; i <= n; i++)
scanf("%d", &K[i]);
int nw = 0, _max = 0;
for (int i = 1; i <= n; i++)
{
int a = A[i], k = K[i];
if (__builtin_popcount(a) < k)
continue;
pair < int , int > Mx = {0, 0};
for (int j = 0; j < SQ; j++)
if (k - __builtin_popcount((a >> 10) & j) >= 0)
MAX(Mx, dp[j][a & (SQ - 1)][k - __builtin_popcount((a >> 10) & j)]);
Mx.first ++;
P[i] = Mx.second;
Mx.second = i;
for (int j = 0; j < SQ; j++)
MAX(dp[a >> 10][j][__builtin_popcount(a & (SQ - 1) & j)], Mx);
if (Mx.first > _max)
_max = Mx.first, nw = i;
}
if (!nw) nw = 1;
while (nw)
{
R[ts ++] = nw;
nw = P[nw];
}
printf("%d\n", ts);
for (int i = ts - 1; ~i; i--)
printf("%d ", R[i]);
return 0;
}
Compilation message (stderr)
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