This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// In the name of the God
#include <bits/stdc++.h>
#define ll long long
// #define int long long
#define pb push_back
#define F first
#define S second
#define mp make_pair
#define pii pair <int, int>
#define smin(x, y) (x) = min((x), (y))
#define smax(x, y) (x) = max((x), (y))
#define all(x) (x).begin(), (x).end()
using namespace std;
// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2")
const int inf = 1e9+7;
const int mod = 998244353;
const int maxn = 20;
int l, q, dp1[1<<maxn], dp2[1<<maxn];
string s, t;
int32_t main() {
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
cin >> l >> q >> s;
for (int i = 0; i < (1<<l); i++) dp1[i] = dp2[(1<<l)-i-1] = s[i]-'0';
for (int i = 0; i < l; i++) {
for (int j = 0; j < (1<<l); j++) {
if (j&(1<<i)) dp1[j] += dp1[j^(1<<i)], dp2[j] += dp2[j^(1<<i)];
}
}
while (q--) {
int cnt0 = 0, cnt1 = 0, cnt2 = 0, m1 = 0, m2 = 0, ans = 0;
cin >> t;
reverse(all(t));
for (int i = 0; i < l; i++) {
if (t[i] == '0') cnt0++;
else if (t[i] == '1') cnt1++;
else cnt2++;
}
// cout << cnt0 << ' ' << cnt1 << ' ' << cnt2 << '\n';
if (cnt0 <= min(cnt1, cnt2)) {
// cout << "HI1\n";
for (int i = 0; i < l; i++) {
if (t[i] == '0') m1 |= (1<<i);
else if (t[i] == '?') m2 |= (1<<i);
}
for (int sm = m1; sm; sm = (sm-1)&m1) {
if (__builtin_parity(m1^sm)) ans -= dp2[sm^m2];
else ans += dp2[sm^m2];
}
if (__builtin_parity(m1)) ans -= dp2[m2];
else ans += dp2[m2];
cout << ans << '\n';
}
else if (cnt1 <= min(cnt0, cnt2)) {
// cout << "HI2\n";
for (int i = 0; i < l; i++) {
if (t[i] == '1') m1 |= (1<<i);
else if (t[i] == '?') m2 |= (1<<i);
}
for (int sm = m1; sm; sm = (sm-1)&m1) {
if (__builtin_parity(m1^sm)) ans -= dp1[sm^m2];
else ans += dp1[sm^m2];
}
if (__builtin_parity(m1)) ans -= dp1[m2];
else ans += dp1[m2];
cout << ans << '\n';
}
else {
// cout << "HI3\n";
for (int i = 0; i < l; i++) {
if (t[i] == '?') m1 |= (1<<i);
else if (t[i] == '1') m2 |= (1<<i);
}
for (int sm = m1; sm; sm = (sm-1)&m1) ans += s[sm^m2]-'0';
ans += s[m2]-'0';
cout << ans << '\n';
}
}
return 0;
}
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