Submission #941145

#	Time	Username	Problem	Language	Result	Execution time	Memory
941145		Pring	Let's Win the Election (JOI22_ho_t3)	C++17	10 / 100	11 ms	464 KiB

Main

#include <bits/stdc++.h>
using namespace std;

#ifdef MIKU
const string dbmc = "\033[1;38;2;57;197;187m", dbrs = "\033[0m";
#define debug(x...) cout << dbmc << "[" << #x << "]: ", dout(x)
void dout() { cout << dbrs << endl; }
template <typename T, typename ...U>
void dout(T t, U ...u) { cout << t << (sizeof...(u) ? ", " : ""); dout(u...); }
#else
#define debug(...) 39
#endif

#define int long long
#define fs first
#define sc second
#define mp make_pair
#define FOR(i, j, k) for (int i = j, Z = k; i < Z; i++)
typedef pair<int, int> pii;

const int MXN = 505;
int n, k;
pii p[MXN];

double calc(int x) {
    sort(p, p + n, [](pii a, pii b) -> bool {
        if (a.sc == -1 && b.sc == -1) return a.fs < b.fs;
        if (a.sc == -1) return false;
        if (b.sc == -1) return true;
        return a.sc < b.sc;
    });
    sort(p + x, p + n, [](pii a, pii b) -> bool {
        return a.fs < b.fs;
    });
    double ans = 0.0;
    // FOR(i, 0, n) cout << p[i].fs << ' ' << p[i].sc << '\n';
    FOR(i, 0, x) ans += (double) p[i].sc / (i + 1);
    FOR(i, x, k) ans += (double) p[i].fs / (x + 1);
    return ans;
}

void miku() {
    cin >> n >> k;
    FOR(i, 0, n) cin >> p[i].fs >> p[i].sc;
    int x = count_if(p, p + n, [](pii a) -> bool {
        return a.sc != -1;
    });
    double ans = 3.9e18;
    FOR(i, 0, min(x, k) + 1) {
        double x = calc(i);
        debug(x);
        ans = min(ans, x);
    }
    cout << fixed << setprecision(10) << ans << '\n';
}

int32_t main() {
    cin.tie(0) -> sync_with_stdio(false);
    cin.exceptions(cin.failbit);
    miku();
    return 0;
}

Compilation message (stderr)

Main.cpp: In function 'void miku()':
Main.cpp:11:20: warning: statement has no effect [-Wunused-value]
   11 | #define debug(...) 39
      |                    ^~
Main.cpp:51:9: note: in expansion of macro 'debug'
   51 |         debug(x);
      |         ^~~~~

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 0 / 11
• Subtask 4: 0 / 12
• Subtask 5: 0 / 33
• Subtask 6: 0 / 11
• Subtask 7: 0 / 23