Submission #937796

#	Time	Username	Problem	Language	Result	Execution time	Memory
937796		Gromp15	Let's Win the Election (JOI22_ho_t3)	C++17	77 / 100	2544 ms	1864 KiB

Main

#include <bits/stdc++.h>
#define ll long long
#define ar array
#define db double
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define rint(l, r) uniform_int_distribution<int>(l, r)(rng)
template<typename T> bool ckmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; }
template<typename T> bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; }
void test_case() {
	int n, k;
	cin >> n >> k;
	vector<ar<int, 2>> a(n);
	for (auto &x : a) cin >> x[0] >> x[1];
	if (n == k) {
		db ans = 1e18;
		int cnt = 0;
		for (int i = 0; i < n; i++) cnt += bool(~a[i][1]);
		sort(all(a), [&](const auto &A, const auto &B) { return A[1] < B[1]; });
		for (int i = 1; i <= min(cnt, k) + 1; i++) {
			// use i people in the end
			vector<db> dp(i+1, 1e18);
			dp[1] = 0;
			for (int j = 0; j < n; j++) {
				vector<db> dp2(i+1, 1e18);
				for (int l = 1; l <= i; l++) {
					if (~a[j][1] && l + 1 <= i) {
						ckmin(dp2[l+1], dp[l] + (db)a[j][1] / l);
					}
					ckmin(dp2[l], dp[l] + (db)a[j][0] / i);
				}
				swap(dp, dp2);
			}
			ckmin(ans, dp[i]);
		}
		cout << fixed << setprecision(10) << ans << '\n';
		return;
	}
	// let us use z people in the end
	// then, we must first take z-1 Bs, and those Bs will be taken in increasing order
	// As must be taken afterwards and can be taken in arbitrary order
	db ans = 1e18;
	int cnt = 0;
	for (int i = 0; i < n; i++) cnt += bool(~a[i][1]);
	sort(all(a), [&](const auto &A, const auto &B) { return A[1] < B[1]; });
	auto get = [&](int i) {
		vector<vector<db>> dp(k+1, vector<db>(i+1, 1e18));
		dp[0][1] = 0;
		for (int j = 0; j < n; j++) {
			for (int got = k-1; got >= 0; got--) {
				for (int l = 1; l <= i; l++) {
					if (~a[j][1] && l + 1 <= i) {
						ckmin(dp[got+1][l+1], dp[got][l] + (db)a[j][1] / l);
					}
					ckmin(dp[got+1][l], dp[got][l] + (db)a[j][0] / i);
				}
			}
		}
		return dp[k][i];
	};
	int L = 1, R = min(cnt, k) + 1;
	while (R - L >= 3) {
		int mid = (L+R)/2;
		if (get(mid) < get(mid+1)) R = mid;
		else L = mid+1;
	}
	for (int i = L; i <= R; i++) ckmin(ans, get(i));
	cout << fixed << setprecision(10) << ans << '\n';
		


}
int main() {
    cin.tie(0)->sync_with_stdio(0);
    int t = 1;
//    cin >> t;
    while (t--) test_case();
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 11 / 11
• Subtask 4: 12 / 12
• Subtask 5: 33 / 33
• Subtask 6: 11 / 11
• Subtask 7: 0 / 23