Submission #93517

#	Time	Username	Problem	Language	Result	Execution time	Memory
93517		dfistric	Pictionary (COCI18_pictionary)	C++14	140 / 140	413 ms	15860 KiB

pictionary

#include <bits/stdc++.h>

#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define FORd(i, a, b) for (int i = (a); i >= (b); i--)
#define REP(i, n) FOR(i, 0, n)

typedef long long ll;

using namespace std;

const int MAXN = 1e5 + 10;
int lo[MAXN], hi[MAXN];
vector <int> mi[MAXN];
int a[MAXN], b[MAXN];
int par[MAXN];

int nadi(int x) {
  if (x != par[x]) par[x] = nadi(par[x]);
  return par[x];
}

void spoji(int x, int y) {
  x = nadi(x);
  y = nadi(y);
  par[y] = x;
  return;
}

int main() {
  ios_base::sync_with_stdio(false);

  int n, m, q;
  cin >> n >> m >> q;

  REP(i, q) {
    cin >> a[i] >> b[i];
    lo[i] = 1;
    hi[i] = m;
  }

  REP(bi, 20) {
    REP(i, n + 1) par[i] = i;

    REP(i, q) {
      int mid = (lo[i] + hi[i]) / 2;
      mi[mid].push_back(i);
    }

    FORd(k, m, 1) {
      int st = k + k;
      while (st <= n) {
        spoji(k, st);
        st += k;
      }

      int p = m - k + 1;
      for (int ne : mi[p]) {
        if (nadi(a[ne]) == nadi(b[ne])) {
          hi[ne] = p;
        } else {
          lo[ne] = p + 1;
        }
      }
      mi[p].clear();
    }
  }

  REP(i, q) cout << lo[i] << "\n";

  return 0;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 14 / 14
• Subtask 4: 14 / 14
• Subtask 5: 14 / 14
• Subtask 6: 14 / 14
• Subtask 7: 14 / 14
• Subtask 8: 14 / 14
• Subtask 9: 14 / 14
• Subtask 10: 14 / 14