# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
933644 | mgch | Round words (IZhO13_rowords) | C++14 | 2070 ms | 20056 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
/** so there is complicated algo based on some research let's get it later
*
*
* you have to get that |lcs(a, b) - lcs(a, b[1..n-1] + b[0])| <= 2
* so if you have ans >= lcs(a, b) + 2 then ... push it
* */
const int N = 2024;
int dp[N][N], n, m;
string s[N], t[N];
int lcs(const string &a, const string &b) {
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
dp[i + 1][j + 1] = max(dp[i + 1][j], dp[i][j + 1]);
if (a[i] == b[j]) {
dp[i + 1][j + 1] = max(dp[i + 1][j + 1], dp[i][j] + 1);
}
}
}
return dp[n][m];
}
int main() {
// freopen("rowords.in", "r", stdin); freopen("rowords.out", "w", stdout);
string a, b;
getline(cin, a);
getline(cin, b);
n = a.length();
m = b.length();
int ans = 0;
for (int i = 0; i < n; ++i) {
s[i] = a.substr(i) + a.substr(0, i);
}
for (int i = 0; i < m; ++i) {
t[i] = b.substr(i) + b.substr(0, i);
}
for (int i = 0; i < 1; ++i) {
for (int j = 0; j < m; ++j) {
ans = max(ans, lcs(s[i], t[j]));
}
}
cout << ans << '\n';
return 0;
}
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
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