Submission #933537

#TimeUsernameProblemLanguageResultExecution timeMemory
933537JuanJLCyberland (APIO23_cyberland)C++17
97 / 100
3018 ms96760 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #define fst first #define snd second #define pb push_back #define forn(i,a,b) for(int i = a; i < b; i++) #define ALL(x) x.begin(),x.end() #define SZ(x) (int)x.size() #define mset(a,v) memset((a),(v),sizeof(a)) #define FIN ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define dbg(v) cout<<"Line("<<__LINE__<<"): "<<#v<<" = "<<v<<'\n'; #define pi pair<int,int> #define pll pair<ll,ll> typedef int ll; using namespace std; using namespace __gnu_pbds; typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> indexed_set; typedef tree<int,null_type,less_equal<int>,rb_tree_tag,tree_order_statistics_node_update> indexed_multiset; ll n,m,k,h; vector<pll> adj[(ll)1e5+5]; bool disp[(ll)1e5+5]; void dfs(ll nd){ if(disp[nd]) return; disp[nd]=1; if(nd==h) return; for(auto i:adj[nd]) dfs(i.fst); } double solve(int N, int M, int K, int H, std::vector<int> x, std::vector<int> y, std::vector<int> c, std::vector<int> arr){ n=N;m=M;k=min((ll)K,(ll)70);h=H; forn(i,0,n) disp[i]=0,adj[i].clear(); forn(i,0,SZ(x)) adj[x[i]].pb({y[i],c[i]}),adj[y[i]].pb({x[i],c[i]}); dfs(0); vector<vector<double>> dist(n+5,vector<double>(k+1,-1)); priority_queue<pair<double,pair<ll,ll>>> pq; pq.push({0,{0,0}}); forn(i,0,k+1) dist[0][i]=0; forn(i,0,n){ if(arr[i]==0&&disp[i]){ pq.push({0,{i,0}}); dist[i][0]=0; //forn(j,0,k+1) dist[i][j]=0; } } double cost; ll nd; ll p2; ll ndV; double nCost; while(!pq.empty()){ cost = pq.top().fst*-1; nd = pq.top().snd.fst; p2 = pq.top().snd.snd; pq.pop(); if(cost>dist[nd][p2]) continue; if(nd==h) continue; for(auto i:adj[nd]){ ndV = i.fst; nCost = i.snd+cost; if(arr[ndV]==0) continue; if(nCost<dist[ndV][p2]||dist[ndV][p2]==-1){ dist[ndV][p2]=nCost; pq.push({dist[ndV][p2]*-1,{ndV,p2}}); } if(arr[ndV]==2&&p2+1<min((ll)k+1,(ll)k+1)){ nCost/=2; if(nCost<dist[ndV][p2+1]||dist[ndV][p2+1]==-1){ dist[ndV][p2+1]=nCost; pq.push({dist[ndV][p2+1]*-1,{ndV,p2+1}}); } } } } double res = -1; forn(i,0,k+1) if(dist[h][i]!=-1&&(res>dist[h][i]||res==-1)) res = dist[h][i]; return (double)res; //return Dijkstra(); }
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