Submission #931868

#	Time	Username	Problem	Language	Result	Execution time	Memory
931868		djs100201	Permutation (APIO22_perm)	C++17	0 / 100	0 ms	348 KiB

perm

#include<bits/stdc++.h>
#include<perm.h>
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("avx2")
#define all(v) v.begin(),v.end()
using namespace std;
using ll = long long;
using P = pair<ll, ll>;
using PP = pair<ll, P>;
const ll n_ =4e5+100, inf = (ll)2e9 * (ll)1e9 + 7, mod = 998244353;
ll n, m, tc = 1, a, b, c, d, sum, x, y, z, base, ans, k;
ll gcd(ll x,ll y){
	if(!y)return x;
	return gcd(y,x%y);
}
vector<int> construct_permutation(long long k){
    vector<int>res,A;
    x=k-1;
    while(x){
        a=x%4; 
        if(x==2){
            res.push_back(1);
            res.push_back(0);
            break;
        }
        else if(x==1){
            res.push_back(0);
            break;
        }
        else if(x==4){
            res.push_back(1);
            res.push_back(2);
            res.push_back(0);
          	break;
        }
        else if(x==3){
            res.push_back(0);
            res.push_back(1);
            break;
        }
        if(a==0){
            A.push_back(-1);
            A.push_back(1);
            A.push_back(1);
            x=(x-4)/4;
        }
        else if(a==1){
            A.push_back(1);
            A.push_back(2);
            x=(x-1)/4-1;
        }
        else if(a==2){
            A.push_back(2);
            A.push_back(1);
            x=(x-2)/4-1;
        }
        else if(a==3){
            A.push_back(1);
            A.push_back(1);
            x=(x-3)/4;
        }
    }
    reverse(all(A));
    for(auto nxt:A){
        if(nxt==1){
            res.push_back(res.size());
        }
        else if(nxt==-1){
            for(auto &i:res)i++;
            res.push_back(0);
        }
        else{
            for(auto &i:res)i++;
            res.push_back(res.size()+1);
            res.push_back(0);

        }
    }
    return res;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 90