Submission #931447

#	Time	Username	Problem	Language	Result	Execution time	Memory
931447		mariaclara	Shortcut (IOI16_shortcut)	C++17	0 / 100	1 ms	500 KiB

shortcut

#include "shortcut.h"
#include<bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef pair<int,int> pii;
const int MAXN = 1e6+5;
#define all(x) x.begin(), x.end()
#define mk make_pair
#define pb push_back
#define f first
#define s second

ll find_shortcut(int n, vector<int> l, vector<int> d, int c) {
    vector<ll> diam_L(n), diam_R(n), dist_L(n), dist_R(n);
    
    dist_L[0] = diam_L[0] = d[0];
    for(int i = 1; i < n; i++) {
        dist_L[i] = max((ll)d[i], dist_L[i-1] + l[i-1]);
        diam_L[i] = max(diam_L[i-1], dist_L[i-1] + l[i-1] + d[i]);
    }

    dist_R[n-1] = diam_R[n-1] = d[n-1];
    for(int i = n-2; i >= 0; i--) {
        dist_R[i] = max((ll)d[i], dist_R[i+1] + l[i]);
        diam_R[i] = max(diam_R[i+1], dist_R[i+1] + l[i] + d[i]);
    }
    
    ll resp = 1e18;
    for(int i = 0; i < n; i++) { // escolhendo onde resp1 vai estar
        ll sum = 0;
        for(int j = i+1; j < n; j++) { // escolhendo onde resp2 vai estar
            sum += l[j-1];
            ll diam = max({diam_R[i+1], diam_L[j-1], dist_L[i] + dist_R[j] + min((ll)c, sum)});
            resp = min(resp, diam);
        }
    }

    return resp;
}

• Subtask 1: 0 / 9
• Subtask 2: 0 / 14
• Subtask 3: 0 / 8
• Subtask 4: 0 / 7
• Subtask 5: 0 / 33
• Subtask 6: 0 / 22
• Subtask 7: 0 / 4
• Subtask 8: 0 / 3