Submission #931327

#	Time	Username	Problem	Language	Result	Execution time	Memory
931327		vjudge1	Fruits (NOI22_fruits)	C++17	5 / 100	76 ms	18516 KiB

Main

#include <bits/stdc++.h>
using namespace std;

#define int long long

const int N = 5e5+5, M = 5e3+3, inf = LLONG_MAX;

int n, mxA, mxC, a[N], c[N], pre[N], preDp[N], dp[M][M];
bitset<N> vis;

signed main() {
  ios::sync_with_stdio(false); cin.tie(nullptr);

  cin >> n;
  mxA = mxC = -inf;
  for (int i = 0; i < n; i++) {
    cin >> a[i];
    if (a[i] != -1) {
      a[i]--;
      vis[a[i]] = 1;
    }
    mxA = max(mxA, a[i]);
  }
  for (int i = 0; i < n; i++) {
    cin >> c[i];
    mxC = max(mxC, c[i]);
  }

  for (int i = 0; i < n; i++) {
    pre[i] = max((i ? pre[i-1] : -1), a[i]);
  }

  if (mxA == -1) {
    int sum = 0;
    for (int i = n-1; i >= 0; i--) {
      sum += c[i];
      cout << sum << " ";
    }
    cout << "\n";
  }
  else if (mxC == 1) {
    int l = 0;
    int ans = 0;
    for (int i = 0; i < n; i++) {
      if (a[i] == -1) {
        while (vis[l]) l++;
        if (l < n) {
          l++;
          ans++;
        }
      }
      else {
        if (l <= a[i]) {
          ans++;
        }
        l = max(l, a[i]+1);
      }
      cout << ans << " ";
    }
    cout << "\n";
  }
  else {
    for (int j = 0; j < n; j++) {
      if ((a[0] == -1 && !vis[j]) || a[0] == j) dp[0][j] = c[j];
      else dp[0][j] = 0;

      preDp[j] = max((j ? preDp[j-1] : 0), dp[0][j]);
    }

    for (int i = 1; i < n; i++) {
      for (int j = 0; j < n; j++) {
        // dp[i][j] = max coste con los i primeros donde el mas grande es j
        dp[i][j] = 0;
        if (pre[i] > j) continue;

        if (a[i] == -1) {
          if (pre[i] < j) {
            if (!vis[j]) dp[i][j] = max(dp[i-1][j], (j ? preDp[j-1] : 0) + c[j]);
          }
          else {
            dp[i][j] = dp[i-1][j];
          }
        }
        else {
          if (a[i] == j) dp[i][j] = (j ? preDp[j-1] : 0) + c[j];
          else {
            dp[i][j] = dp[i-1][j];
          }
        }//cerr << i << " " << j << " " << dp[i][j] << endl;
      }

      for (int j = 0; j < n; j++) {
        preDp[j] = max((j ? preDp[j-1] : 0), dp[i][j]);
      }
    }

    for (int i = 0; i < n; i++) {
      int ans = 0;
      for (int j = pre[i]; j < n; j++) {
        ans = max(ans, dp[i][j]);
      }
      cout << ans << " ";
    }
    cout << "\n";
  }
}

• Subtask 1: 0 / 6
• Subtask 2: 5 / 5
• Subtask 3: 0 / 11
• Subtask 4: 0 / 13
• Subtask 5: 0 / 23
• Subtask 6: 0 / 42