Submission #927655

#	Time	Username	Problem	Language	Result	Execution time	Memory
927655		IBory	코알라 (JOI13_koala)	C++17	0 / 100	126 ms	9316 KiB

koala

#include <bits/stdc++.h>
typedef long long ll;
using namespace std;

const ll SZ = 1 << 17, INF = 2E18;
ll P[SZ], B[SZ], dp[SZ];

struct Seg {
	ll T[SZ << 1], Z[SZ << 1];
	Seg() {
		fill(T, T + SZ * 2, -INF);
	}
	void Push(int n) {
		if (n < SZ) {
			Z[n * 2] += Z[n];
			Z[n * 2 + 1] += Z[n];
		}
		T[n] += Z[n];
		Z[n] = 0;
	}
	void Update(int L, int R, ll v, int sL = 1, int sR = SZ, int n = 1) {
		Push(n);
		if (R < sL || sR < L) return;
		if (L <= sL && sR <= R) {
			Z[n] += v;
			Push(n);
			return;
		}
		int mid = (sL + sR) >> 1;
		Update(L, R, v, sL, mid, n * 2);
		Update(L, R, v, mid + 1, sR, n * 2 + 1);
		T[n] = max(T[n * 2], T[n * 2 + 1]);
	}
	ll Query(int L, int R, int sL = 1, int sR = SZ, int n = 1) {
		Push(n);
		if (R < sL || sR < L) return -INF;
		if (L <= sL && sR <= R) return T[n];
		int mid = (sL + sR) >> 1;
		return max(Query(L, R, sL, mid, n * 2), Query(L, R, mid + 1, sR, n * 2 + 1));
	}
} T;

int Get(vector<int>& S, int n) {
	return (lower_bound(S.begin(), S.end(), n) - S.begin());
}

int main() {
	ios::sync_with_stdio(0); cin.tie(0);
	ll SP, EP, D, A, N;
	cin >> SP >> EP >> D >> A >> N;
	for (int i = 1; i <= N; ++i) cin >> P[i] >> B[i];
	P[0] = SP, P[N + 1] = EP;

	vector<int> mod;
	for (int i = 0; i <= N + 1; ++i) mod.push_back(P[i] % D);
	mod.push_back(-1);
	sort(mod.begin(), mod.end());
	mod.erase(unique(mod.begin(), mod.end()), mod.end());
	int init = Get(mod, P[0] % D);
	T.Update(init, init, INF);

	for (int i = 1; i <= N + 1; ++i) {
		int cur = Get(mod, P[i] % D);

		ll diff = P[i] - P[i - 1], mv = diff / D, more = diff % D;
		T.Update(1, SZ, -mv * A);
		if (more) {
			int a = Get(mod, P[i - 1] % D), b = Get(mod, ((P[i - 1] % D) + more) % D);
			if (a < b) T.Update(a, b - 1, -A);
			else {
				T.Update(a, SZ, -A);
				if (1 < b) T.Update(1, b - 1, -A);
			}
		}

		ll pv = T.Query(cur, cur);
		dp[i] = T.Query(1, SZ) + B[i];
		T.Update(cur, cur, -pv + dp[i]);
	}

	cout << dp[N + 1] << '\n';
	return 0;
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 30
• Subtask 3: 0 / 50