Submission #927586

#	Time	Username	Problem	Language	Result	Execution time	Memory
927586		Tuanlinh123	Amusement Park (JOI17_amusement_park)	C++17	10 / 100	43 ms	25284 KiB

Joi

#include "Joi.h"
#include<bits/stdc++.h>
#define ll long long
#define pll pair<ll, ll>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ld long double
using namespace std;

void Joi(int n, int m, int u[], int v[], ll x, int t) 
{
    vector <vector <ll>> A(n);
    for (ll i=0; i<m; i++)
        A[u[i]].pb(v[i]), A[v[i]].pb(u[i]);
    vector <vector <ll>> order(n);
    vector <ll> col(n, -1);
    auto getfirst60=[&]()
    {
        ll cnt=0;
        function<void(ll)> dfs=[&](ll u)
        {
            if (cnt>=60) return;
            col[u]=cnt++;
            for (ll v:A[u])
                if (col[v]==-1)
                    dfs(v);
        }; dfs(0);
        vector <bool> check(n, 0);
        function<void(ll, ll)> dfs1=[&](ll u, ll r)
        {
            check[u]=1;
            if (u!=r) order[r].pb(u);
            for (ll v:A[u])
                if (!check[v] && col[v]>=0)
                    dfs1(v, r), order[r].pb(u);
        };
        for (ll i=0; i<n; i++) if (col[i]>=0)
            check.assign(n, 0), dfs1(i, i);
    }; getfirst60();
    queue <ll> q;
    for (ll i=0; i<n; i++)
        if (col[i]>=0) q.push(i);
    while (!q.empty())
    {
        ll u=q.front(); q.pop();
        for (ll v:A[u]) if (col[v]==-1)
        {
            col[v]=col[order[u].back()], order[v].pb(u), q.push(v);
            for (ll j:order[u]) order[v].pb(j); order[v].pop_back();
        }
    }
    for (ll i=0; i<n; i++) MessageBoard(i, (x>>col[i])&1);
}

Ioi

#include "Ioi.h"
#include<bits/stdc++.h>
#define ll long long
#define pll pair<ll, ll>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ld long double
using namespace std;

ll Ioi(int n, int m, int u[], int v[], int p, int cr, int t) 
{
    vector <vector <ll>> A(n);
    for (ll i=0; i<m; i++)
        A[u[i]].pb(v[i]), A[v[i]].pb(u[i]);
    vector <vector <ll>> order(n);
    vector <ll> col(n, -1);
    auto getfirst60=[&]()
    {
        ll cnt=0;
        function<void(ll)> dfs=[&](ll u)
        {
            if (cnt>=60) return;
            col[u]=cnt++;
            for (ll v:A[u])
                if (col[v]==-1)
                    dfs(v);
        }; dfs(0);
        vector <bool> check(n, 0);
        function<void(ll, ll)> dfs1=[&](ll u, ll r)
        {
            check[u]=1;
            if (u!=r) order[r].pb(u);
            for (ll v:A[u])
                if (!check[v] && col[v]>=0)
                    dfs1(v, r), order[r].pb(u);
        };
        for (ll i=0; i<n; i++) if (col[i]>=0)
            check.assign(n, 0), dfs1(i, i);
    }; getfirst60();
    queue <ll> q;
    for (ll i=0; i<n; i++)
        if (col[i]>=0) q.push(i);
    while (!q.empty())
    {
        ll u=q.front(); q.pop();
        for (ll v:A[u]) if (col[v]==-1)
        {
            col[v]=col[order[u].back()], order[v].pb(u), q.push(v);
            for (ll j:order[u]) order[v].pb(j); order[v].pop_back();
        }
    }
    ll ans=0;
    for (ll i:order[p]) ans|=(ll)Move(i)<<col[i];
    return ans;
}

Compilation message (stderr)

Joi.cpp: In function 'void Joi(int, int, int*, int*, long long int, int)':
Joi.cpp:51:13: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   51 |             for (ll j:order[u]) order[v].pb(j); order[v].pop_back();
      |             ^~~
Joi.cpp:51:49: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   51 |             for (ll j:order[u]) order[v].pb(j); order[v].pop_back();
      |                                                 ^~~~~

Ioi.cpp: In function 'long long int Ioi(int, int, int*, int*, int, int, int)':
Ioi.cpp:51:13: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   51 |             for (ll j:order[u]) order[v].pb(j); order[v].pop_back();
      |             ^~~
Ioi.cpp:51:49: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   51 |             for (ll j:order[u]) order[v].pb(j); order[v].pop_back();
      |                                                 ^~~~~

• Subtask 1: 0 / 8
• Subtask 2: 0 / 10
• Subtask 3: 10 / 10
• Subtask 4: 0 / 55
• Subtask 5: 0 / 17