Submission #927342

#	Time	Username	Problem	Language	Result	Execution time	Memory
927342		VMaksimoski008	Connecting Supertrees (IOI20_supertrees)	C++14	21 / 100	167 ms	22580 KiB

supertrees

#include <bits/stdc++.h>
#include "supertrees.h"

#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
//#define int long long

using namespace std;

using ll = long long;
using ull = unsigned long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;

const int mod = 1e9 + 7;
const int LOG = 20;
const int maxn = 1e5 + 5;
const double eps = 1e-9;

struct DSU {
    int n, comp;
    vector<int> par, size;

    void config(int _n) {
        n = _n + 1;
        comp = _n;
        par.resize(n+1);
        size.resize(n+1, 1);
        for(int i=1; i<=n; i++) par[i] = i;
    }

    int get(int u) {
        if(u == par[u]) return u;
        return par[u] = get(par[u]);
    }

    bool uni(int u, int v) {
        u = get(u), v = get(v);

        if(u == v) return false;
        if(size[u] < size[v]) swap(u, v);

        size[u] += size[v];
        par[v] = u;
        comp--;

        return true;
    }

    int getComp() { return comp; }
    int getSize(int u) { return size[get(u)]; }
    bool sameSet(int u, int v) { return get(u) == get(v); }
};

int construct(vector<vector<int> > p) {
    int n = p.size();
    vector<int> cnt(3);

    for(int i=0; i<n; i++)
        for(int j=0; j<n; j++) if(i != j) cnt[p[i][j]]++;

    if(!cnt[2] && !cnt[3]) {
        DSU dsu; dsu.config(n);
        vector<vector<int> > B(n, vector<int>(n, 0));

        for(int i=0; i<n; i++) {
            for(int j=0; j<n; j++) {
                if(p[i][j] == 1)
                    if(dsu.uni(i, j)) B[i][j] = B[j][i] = 1;
            }
        }

        for(int i=0; i<n; i++) {
            for(int j=0; j<n; j++) {
                if(p[i][j] == 1 && !dsu.sameSet(i, j)) return 0;
                if(p[i][j] == 0 && dsu.sameSet(i, j)) return 0;
            }
        }

        build(B);
        return 1;
    } else if(!cnt[1] && !cnt[3]) {
        
    }

    return 1;
}

• Subtask 1: 11 / 11
• Subtask 2: 10 / 10
• Subtask 3: 0 / 19
• Subtask 4: 0 / 35
• Subtask 5: 0 / 21
• Subtask 6: 0 / 4