Submission #9267

#TimeUsernameProblemLanguageResultExecution timeMemory
9267lhch6759N-orthotope (kriii2_N)C++98
0 / 4
0 ms1672 KiB
// 제2회 kriiICPC // // #include <iostream> #include <vector> using namespace std; int main(){ int case_num; cin >> case_num; int A[12][2]; int B[12][2]; int orthotope[12]; //안겹칠 경우 -1, 한점에서 만나는경우 0, 선이 겹치는 경우 1 //input for (int nc = 0; nc < case_num; nc++){ orthotope[nc] = -1; for (int n = 0; n < 2; n++){ cin >> A[nc][n]; } } for (int nc = 0; nc < case_num; nc++){ for (int n = 0; n < 2; n++){ cin >> B[nc][n]; } } // for (int i = 0; i < case_num; i++){ // B 안에 A if (A[i][1] == B[i][0] || B[i][0] == A[i][1]) orthotope[i] = 0; if (A[i][1] < B[i][1] && B[i][0] < A[i][1]) orthotope[i] = 1; if (B[i][0] < A[i][0] && A[i][0] < B[i][1]) orthotope[i] = 1; } int result = 0; for (int i = 0; i < case_num; i++){ if (orthotope[i] > 0){ result++; } } //output cout << result << endl; }
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