Submission #923150

#TimeUsernameProblemLanguageResultExecution timeMemory
923150myst6Zoltan (COCI16_zoltan)C++14
140 / 140
194 ms15992 KiB
#include <bits/stdc++.h> using namespace std; // put all numbers left-to-right // and get M and C(ount) // can move any selection of the N-M numbers across for each of the C seqs // so ans = C * 2^(N-M) using ll = long long; const ll mod = 1'000'000'007LL; struct Info { int m, ct; Info(int M, int C) : m(M), ct(C%mod) {} Info() : Info(0, 0) {} Info combine(Info &other) { if (m == other.m) return {m, ct + other.ct}; else if (m > other.m) return {m, ct}; else return {other.m, other.ct}; } }; struct Tree { vector<Info> info; Tree(int size) { info.resize(size*4); } void update(int v, int x, int xl, int xr, Info delta) { if (xl == xr) { info[x] = delta; } else { int xm = (xl + xr) / 2; if (v <= xm) update(v, x*2, xl, xm, delta); else update(v, x*2+1, xm+1, xr, delta); info[x] = info[x*2].combine(info[x*2+1]); } } Info query(int l, int r, int x, int xl, int xr) { if (l > r) return {}; if (l == xl && r == xr) { return info[x]; } else { int xm = (xl + xr) / 2; Info left = query(l, min(r, xm), x*2, xl, xm); Info right = query(max(l, xm+1), r, x*2+1, xm+1, xr); return left.combine(right); } } }; ll modmul(ll a, ll b) { return a * b % mod; } ll modpow(ll a, ll b) { if (b == 0) return 1; if (b == 1) return a; ll half = modpow(a, b/2); ll ans = modmul(half, half); if (b % 2) return modmul(ans, a); else return ans; } int main() { cin.tie(0)->sync_with_stdio(0); int N; cin >> N; vector<int> X(N); for (int i=0; i<N; i++) cin >> X[i]; // find longest increasing subsequence starting at node 'i' vector<int> order(N); iota(order.begin(), order.end(), 0); sort(order.begin(), order.end(), [&](int i, int j) -> bool { if (X[i] == X[j]) return i < j; return X[i] > X[j]; }); Tree tree(N); vector<Info> incr(N); for (int i : order) { Info info = tree.query(i+1, N-1, 1, 0, N-1); info.m += 1; if (info.m == 1) info.ct = 1; // start once tree.update(i, 1, 0, N-1, info); incr[i] = info; } // find longest decreasing subsequence starting at node 'i' tree = Tree(N); sort(order.begin(), order.end(), [&](int i, int j) -> bool { if (X[i] == X[j]) return i < j; return X[i] < X[j]; }); vector<Info> decr(N); for (int i : order) { Info info = tree.query(i+1, N-1, 1, 0, N-1); info.m += 1; if (info.m == 1) info.ct = 1; // start once tree.update(i, 1, 0, N-1, info); decr[i] = info; } Info best; for (int i=0; i<N; i++) { Info here = { decr[i].m + incr[i].m - 1, (int) modmul(decr[i].ct, incr[i].ct), }; best = best.combine(here); } int M = best.m, C = best.ct; cout << M << " " << modmul(C, modpow(2, N-M)) << "\n"; return 0; }
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