# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
92260 | Retro3014 | Islands (IOI08_islands) | C++17 | 527 ms | 131772 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <algorithm>
#include <vector>
#include <deque>
using namespace std;
#define MAX_N 1000000
typedef long long ll;
int N;
struct S{
int idx;
ll data;
};
vector<S> gp[MAX_N+1];
int a, b;
struct C{
ll a, b;
};
S from[MAX_N+1];
vector<S> c;
vector<C> cycle;
bool vst[MAX_N+1];
bool isc[MAX_N+1];
int num[MAX_N+1];
ll len[MAX_N+1];
deque<int> leaf;
ll m[MAX_N+1][3];
ll ans=0;
vector<S> gp2;
int main(){
scanf("%d", &N);
for(int i=1; i<=N; i++){
scanf("%d%d", &a, &b);
gp[i].push_back((S){a, (ll)b}); num[i]++;
gp[a].push_back((S){i, (ll)b}); num[a]++;
}
for(int i=1; i<=N; i++){
if(num[i]==1){
leaf.push_back(i);
}
}
while(!leaf.empty()){
int now=leaf.front(); leaf.pop_front();
vst[now]=true;
m[now][0]=max(m[now][0], m[now][1]+m[now][2]);
for(int i=0; i<gp[now].size(); i++){
if(!vst[gp[now][i].idx]){
len[gp[now][i].idx]=max(len[gp[now][i].idx], len[now]+gp[now][i].data);
m[gp[now][i].idx][0]=max(m[gp[now][i].idx][0], m[now][0]);
if(len[now]+gp[now][i].data>m[gp[now][i].idx][1]){
m[gp[now][i].idx][2]=m[gp[now][i].idx][1];
m[gp[now][i].idx][1]=len[now]+gp[now][i].data;
}else if(len[now]+gp[now][i].data>m[gp[now][i].idx][2]){
m[gp[now][i].idx][2]=len[now]+gp[now][i].data;
}
num[gp[now][i].idx]--;
if(num[gp[now][i].idx]==1){
leaf.push_back(gp[now][i].idx);
}
}
}
}
for(int i=1; i<=N; i++){
if(!vst[i]){
for(int j=0; j<gp[i].size(); j++){
if(!vst[gp[i][j].idx]){
gp2.push_back(gp[i][j]);
}
}
while(!gp[i].empty()) gp[i].pop_back();
while(!gp2.empty()){
gp[i].push_back(gp2.back()); gp2.pop_back();
}
}
}
for(int i=1; i<=N; i++){
if(!vst[i]){
c.push_back({gp[i][1].idx, gp[i][1].data});
int t=i;
while(!c.empty()){
vst[t]=true;
if(vst[gp[t][0].idx]){
if(vst[gp[t][1].idx]){
break;
}
c.push_back({t, gp[t][1].data});
t=gp[t][1].idx;
}else{
c.push_back({t, gp[t][0].data});
t=gp[t][0].idx;
}
}
ll ans2=0;
ll sum=0;
while(!c.empty()){
S now = c.back(); c.pop_back();
ans2=max(ans2, m[now.idx][0]);
sum+=now.data;
cycle.push_back({now.data, len[now.idx]});
}
ll m1=0, m2=0;
while(!cycle.empty()){
C now = cycle.back(); cycle.pop_back();
ans2=max(ans2, max(now.b, max(m1+now.b, m2+now.b)));
m1=max(m1+now.a, now.a+now.b);
m2=max(m2-now.a, sum-now.a+now.b);
}
ans+=ans2;
}
}
printf("%lld", ans);
return 0;
}
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