Submission #920711

#TimeUsernameProblemLanguageResultExecution timeMemory
920711hasuhasuiroAutobahn (COI21_autobahn)C++17
50 / 100
1034 ms132828 KiB
#include <iostream> #include <vector> #include <map> #include <set> #include <algorithm> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int N, K; long long X; cin >> N >> K >> X; vector l(N, 0LL), r(N, 0LL), t(N, 0LL); for(int i = 0; i < N; i++) { cin >> l[i] >> t[i] >> r[i]; r[i]++; } /* 座標圧縮用の座標 */ vector P(0, 0LL); for(int i = 0; i < N; i++) { P.push_back(l[i]), P.push_back(r[i]); } /* 各区間の始点終点 */ for(int i = 0; i < N; i++) { if(l[i]+t[i] < r[i]) { P.push_back(l[i]+t[i]); } } /* 追加料金のかかる区間の始点 */ sort(begin(P), end(P)); P.erase(unique(begin(P), end(P)), end(P)); map<long long, int> mp2; for(int i = 0; i < (int)size(P); i++) { mp2[P[i]] = 1; } int sizep(size(P)); for(int i = 0; i < sizep; i++) { P.push_back(P[i]+X), P.push_back(P[i]-X); if(mp2.find(P[i]+X) == end(mp2)) { mp2[P[i]+X] = 2; } if(mp2.find(P[i]-X) == end(mp2)) { mp2[P[i]-X] = 3; } } /* ある点から X の距離の点 */ sort(begin(P), end(P)); P.erase(unique(begin(P), end(P)), end(P)); /* P の逆引きできるような連想配列 */ map<long long, int> mp; for(int i = 0; i < (int)size(P); i++) { mp[P[i]] = i; } vector imos(size(P), 0); for(int i = 0; i < N; i++) { imos[mp[l[i]]]++; imos[mp[r[i]]]--; } /* 各区間の区間加算 */ for(int i = 0; i+1 < (int)size(P); i++) { imos[i+1] += imos[i]; } /* 求解 */ vector imos2(size(P), 0LL); for(int i = 0; i < N; i++) { if(l[i]+t[i] < r[i]) { imos2[mp[l[i]+t[i]]]++; imos2[mp[r[i]]]--; } } /* 追加料金の区間加算 */ for(int i = 0; i+1 < (int)size(P); i++) { imos2[i+1] += imos2[i]; } /* 求解 */ for(int i = 0; i < (int)size(P); i++) { if(imos[i] < K) { imos2[i] = 0; } } /* 許される場合は除外する */ /* 尺取り法 */ long long ans(0LL), res(0LL); for(int i = 0, j = 0; i+1 < (int)size(P); i++) { if(mp2[P[i]] == 2) { res -= imos2[mp[P[i]]] * (long long)(P[i+1] - P[i]); /* 左端を加算 */ continue; } for(; j < (int)size(P); j++) { if(P[i]+X <= P[j]) { break; } else if(j+1 < (int)size(P)) { res += imos2[mp[P[j]]] * (long long)(P[j+1]-P[j]); } /* 右端を加算 */ else break; } ans = max(res, ans); res -= imos2[mp[P[i]]] * (long long)(P[i+1] - P[i]); /* 左端を加算 */ } cout << ans << endl; return 0; }
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