Submission #920265

#TimeUsernameProblemLanguageResultExecution timeMemory
920265vjudge1Diversity (CEOI21_diversity)C++17
0 / 100
7021 ms344 KiB
#include <iostream> #include <complex> #include <vector> #include <string> #include <algorithm> #include <cstdio> #include <numeric> #include <cstring> #include <ctime> #include <cstdlib> #include <set> #include <map> #include <unordered_map> #include <unordered_set> #include <list> #include <cmath> #include <bitset> #include <cassert> #include <queue> #include <stack> #include <deque> #include <random> using namespace std; template<typename T1, typename T2> inline void chkmin(T1 &a, T2 b) {if (a > b) a = b;} template<typename T1, typename T2> inline void chkmax(T1 &a, T2 b) {if (a < b) a = b;} #define files(FILENAME) read(FILENAME); write(FILENAME) #define read(FILENAME) freopen((FILENAME + ".in").c_str(), "r", stdin) #define write(FILENAME) freopen((FILENAME + ".out").c_str(), "w", stdout) #define all(c) (c).begin(), (c).end() #define sz(c) (int)(c).size() #define left left228 #define right right228 #define y1 y1228 #define mp make_pair #define pb push_back #define y2 y2228 #define rank rank228 using ll = long long; using ld = long double; const string FILENAME = "input"; const int MAXN = 300228; int cnt[MAXN]; ll get(vector<int> a) { ll res = 0; for (int i = 0; i < sz(a); i++) { int diff = 0; for (int j = i; j < sz(a); j++) { if (cnt[a[j]] == 0) { diff++; } cnt[a[j]]++; res += diff; } for (int j = i; j < sz(a); j++) { cnt[a[j]] = 0; } } return res; } int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); //read(FILENAME); int n, q; cin >> n >> q; vector<int> a(n); for (int i = 0; i < n; i++) { cin >> a[i]; } vector<int> inds(n); iota(all(inds), 0); ll cost = 1e18; do { vector<int> newa(n); for (int i = 0; i < n; i++) { newa[inds[i]] = a[i]; } chkmin(cost, get(newa)); } while (next_permutation(all(inds))); cout << cost << '\n'; sort(all(a)); assert(get(a) == cost); return 0; for (int i = 1; i <= q; i++) { int l, r; cin >> l >> r; vector<int> v; for (int j = l; j <= r; j++) { v.pb(a[j - 1]); } sort(all(v)); cout << get(v) << '\n'; } return 0; }
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