Submission #919652

#TimeUsernameProblemLanguageResultExecution timeMemory
919652manizareIntergalactic ship (IZhO19_xorsum)C++14
100 / 100
206 ms17644 KiB
#include <bits/stdc++.h> #pragma GCC optimize ("O3,unroll-loops") #define pb push_back #define F first #define S second #define all(a) a.begin(),a.end() #define pii pair <int,int> #define PII pair<pii , pii> #define int long long #define sz(v) (int)v.size() #define rep(i , a , b) for(int i=a;i <= (b);i++) #define per(i , a , b) for(int i=a;i >= (b);i--) #define deb(x) cout <<#x << " : " << x << "\n" ; using namespace std ; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const int maxn = 2002+ 10 , maxq = 1e6+10 , lg = 18 , inf= 1e9 , mod = 1e9+7 ; int t[maxn] ,prt[maxn] , f[maxn][9] , pr[maxn][8] , a2[maxq] , pr2[maxn][8] , a[maxn]; struct bz{ int l , r , w ; }; bz b[maxq] ; vector <int> L[maxn] , R[maxn] ; signed main(){ ios_base::sync_with_stdio(false);cin.tie(0); a2[0] = 1; rep(i , 1, maxq-1){ a2[i] = a2[i-1] * 2 % mod ; } int n ;cin >> n; rep(i , 1, n){ cin >> a[i] ; } int Q ; cin >> Q; rep(i , 1, Q){ cin >> b[i].l >> b[i].r >> b[i].w; L[b[i].l].pb(i); R[b[i].r].pb(i) ; rep(j , 0 , 6){ pr2[b[i].l][j] += (b[i].w>>j&1) ; pr2[b[i].r+1][j] -= (b[i].w>>j&1) ; } } rep(i , 1, n){ rep(j , 0 , 6){ pr2[i][j] += pr2[i-1][j] ; } } int ans =0 ; rep(k , 0 , 6){ rep(i , 1 , n){ for(int id : L[i]){ if((b[id].w>>k&1) == 0)continue ; rep(z , 0 , 6){ f[b[id].r][z] += (b[id].w>>z&1) ; } } rep(z , 0 , 6){ int sm= 0 ; per(j , n, i){ sm += f[j][z] ; int o[2][2] ; o[1][1] = sm ; o[1][0] = pr2[i][k] - sm; o[0][1] = pr2[j][z] - sm ; o[0][0] = Q - o[0][1] - o[1][0] - o[1][1] ; int Z = i * (n-j+1) % mod * (1ll<<k) %mod * (1ll<<z)%mod; if(i != j)Z = Z * 2 % mod ; if((o[1][1]!=0)+(o[1][0]!=0)+(o[0][1]!=0) >= 2){ ans = (ans + Z * a2[Q-2] % mod)%mod ; }else if((o[1][1]!=0)+(o[1][0]!=0)+(o[0][1]!=0) == 0){ if((a[i]>>k&1) && (a[j]>>z&1))ans = (ans + Z * a2[Q])%mod; }else{ int x1 = 1 , y1 =1 ; if(o[0][1] != 0)x1 = 0; if(o[1][0] != 0)y1 = 0 ; if(((a[i]>>k&1)) && (a[j]>>z&1))ans = (ans + Z * a2[Q-1]) % mod ; if(((a[i]>>k&1)^(x1==1)) && ((a[j]>>z&1)^(y1==1)))ans = (ans + Z * a2[Q-1]) % mod ; } } } } rep(i , 0 , n){ rep(j , 0 , 6){ f[i][j] = 0; } } } cout << ans << "\n"; } /* */
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