Submission #919650

#	Time	Username	Problem	Language	Result	Execution time	Memory
919650		manizare	Intergalactic ship (IZhO19_xorsum)	C++14	45 / 100	175 ms	21328 KiB

xorsum

#include <bits/stdc++.h>
#pragma GCC optimize ("O3,unroll-loops")
#define pb push_back
#define F first
#define S second 
#define all(a) a.begin(),a.end()
#define pii pair <int,int>
#define PII pair<pii , pii>
#define int long long 
#define sz(v) (int)v.size()
#define rep(i , a , b) for(int i=a;i <= (b);i++)
#define per(i , a , b) for(int i=a;i >= (b);i--)
#define deb(x) cout <<#x << " : " << x << "\n" ; 
using namespace std ;   
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int maxn = 1002+ 10 , maxq = 1e6+10 , lg = 18 , inf= 1e9 , mod = 1e9+7 ;
int t[maxn] ,prt[maxn] , f[maxn][9] , pr[maxn][8] , a2[maxq] , pr2[maxn][8] , a[maxn];
 
struct bz{
    int l , r , w ;
};
bz b[maxn] ;
vector <int> L[maxn] , R[maxn] ;
 
signed main(){
	ios_base::sync_with_stdio(false);cin.tie(0);
    a2[0] = 1;
    rep(i , 1, maxq-1){
        a2[i] = a2[i-1] * 2 % mod ;
    }
    int n ;cin >> n; 
    rep(i , 1, n){
        cin >> a[i] ;
    }
    int Q ;
    cin >> Q; 
    rep(i , 1, Q){
        cin >> b[i].l >> b[i].r >> b[i].w;  
        L[b[i].l].pb(i); 
        R[b[i].r].pb(i) ;
        rep(j , 0 , 6){
            pr2[b[i].l][j] += (b[i].w>>j&1) ;
            pr2[b[i].r+1][j] -= (b[i].w>>j&1) ;
        }
    }
    rep(i , 1, n){
        rep(j , 0 , 6){
            pr2[i][j] += pr2[i-1][j] ;
        }
    }
    int ans =0 ;
    rep(k , 0 , 6){
        rep(i , 1 , n){
            for(int id : L[i]){
                if((b[id].w>>k&1) == 0)continue ;
                rep(z , 0 , 6){
                    f[b[id].r][z] += (b[id].w>>z&1) ;
                }
            }
            rep(z , 0 , 6){
                int sm= 0  ;
                per(j , n, i){
                    sm += f[j][z] ;
                    int o[2][2] ;
                    o[1][1] = sm ;
                    o[1][0] = pr2[i][k] - sm;
                    o[0][1] = pr2[j][z] - sm ;
                    o[0][0] = Q - o[0][1] - o[1][0] - o[1][1] ;
                    int Z = i * (n-j+1) % mod * (1ll<<k) %mod * (1ll<<z)%mod;
                    if(i != j)Z = Z * 2 % mod ;
             //       if(k==6 && z==6){
             //           cout << o[0][0] << " "<< o[1][0] << " " << o[0][1] << " " << o[1][1] << " " << Z << " " << a2[Q] << " " <<((a[i]>>k&1) && (a[j]>>z&1))<< "<--\n";
             //       }
                    if((o[1][1]!=0)+(o[1][0]!=0)+(o[0][1]!=0) >= 2){
                        ans = (ans + Z * a2[Q-2] % mod)%mod ;
                    }else if((o[1][1]!=0)+(o[1][0]!=0)+(o[0][1]!=0) == 0){
                        if((a[i]>>k&1) && (a[j]>>z&1))ans = (ans + Z * a2[Q])%mod;
                    }else{
                        int x1 = 1 , y1 =1 ;
                        if(o[0][1] != 0)x1 = 0;
                        if(o[1][0] != 0)y1 = 0 ;
                        if(((a[i]>>k&1)) && (a[j]>>z&1))ans = (ans + Z * a2[Q-1]) % mod ;
                        if(((a[i]>>k&1)^(x1==1)) &&  ((a[j]>>z&1)^(y1==1)))ans = (ans + Z * a2[Q-1]) % mod ;
                    }            
                }
            }
        }
        rep(i , 0 , n){
            rep(j , 0 , 6){
                f[i][j] = 0;
            }
        }
    }
    cout << ans << "\n"; 
}
/*
    
*/

• Subtask 1: 4 / 4
• Subtask 2: 5 / 5
• Subtask 3: 0 / 6
• Subtask 4: 9 / 9
• Subtask 5: 8 / 8
• Subtask 6: 0 / 11
• Subtask 7: 19 / 19
• Subtask 8: 0 / 30
• Subtask 9: 0 / 8