Submission #918484

#	Time	Username	Problem	Language	Result	Execution time	Memory
918484		n3rm1n	K blocks (IZhO14_blocks)	C++17	18 / 100	1 ms	4444 KiB

blocks

#include<bits/stdc++.h>
#define endl '\n'
using namespace std;
const long long MAXN = 1e5 + 10, MAXK = 105;
void speed()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
}
long long n, k, a[MAXN];
void read()
{
    cin >> n >> k;
    for (long long i = 1; i <= n; ++ i)
        cin >> a[i];
}
long long dp[MAXN][MAXK];
long long maxused[MAXN][MAXK];
void solve()
{
    long long inf = 1e17;
    for (int i = 1; i <= n; ++ i)
        for (int j = 0; j <= k; ++ j)
            dp[i][j] = inf;
    dp[0][0] = 0;
    for (long long j = 1; j <= k; ++ j)
    {
        stack < pair <long long, long long > > t;
        ///t.push(make_pair(0, 0));
        for (long long i = j; i <= n; ++ i)
        {
            ///cout << "***" << endl;
            dp[i][j] = inf;
            dp[i][j] = dp[i-1][j-1] + a[i];

            maxused[i][j] = a[i];
            long long init = dp[i][j];
            if(init >= inf)
            {
                maxused[i][j] = inf;

            }
           /// cout << "init " << init << " from " << dp[i-1][j-1] << endl;
            while(!t.empty())
            {
                long long sz = t.top().first;
                long long dpp = t.top().second;

                if(maxused[sz][j] <= a[i])
                {
                    if(dpp + a[i] - maxused[sz][j] < dp[i][j])
                    {
                        dp[i][j] = dpp + a[i] - maxused[sz][j];
                       /// cout <<"updated to " <<  dpp + a[i] - maxused[sz][j] << " from " << sz << endl;
                    }
                    t.pop();
                }
                else break;
            }
            if(t.size() == 0 || t.top().second > dp[i][j])
            {
               /// cout << "if (1) " << endl;
                t.push(make_pair(i, dp[i][j]));
            }
            else
            {
               /// cout << "if (2) " << endl;
                dp[i][j] = t.top().second;
                maxused[i][j] = maxused[t.top().first][j];

            }
           /// cout << i << " " << j << " --> " << dp[i][j] << endl;
           /// cout << "maxused " << maxused[i][j] << endl;
           /// cout << "init was " << init << endl;
        }
    }
    cout << dp[n][k] << endl;
}
int main()
{
    speed();

    read();
    solve();
    return 0;
}

• Subtask 1: 0 / 14
• Subtask 2: 18 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47