oj.uz

답안 #915692

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
915692 2024-01-24T14:45:46 Z tvladm2009 Palembang Bridges (APIO15_bridge) C++17
22 / 100
 38 ms 2248 KB 
#include <iostream>
#include <complex>
#include <vector>
#include <string>
#include <algorithm>
#include <cstdio>
#include <numeric>
#include <cstring>
#include <ctime>
#include <cstdlib>
#include <set>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <list>
#include <cmath>
#include <bitset>
#include <cassert>
#include <queue>
#include <stack>
#include <deque>
#include <random>
 
using namespace std;
template<typename T1, typename T2> inline void chkmin(T1 &a, T2 b) {if (a > b) a = b;}
template<typename T1, typename T2> inline void chkmax(T1 &a, T2 b) {if (a < b) a = b;}
#define files(FILENAME) read(FILENAME); write(FILENAME)
#define read(FILENAME) freopen((FILENAME + ".in").c_str(), "r", stdin)
#define write(FILENAME) freopen((FILENAME + ".out").c_str(), "w", stdout)
#define all(c) (c).begin(), (c).end()
#define sz(c) (int)(c).size()
#define left left228
#define right right228
#define y1 y1228
#define mp make_pair
#define pb push_back
#define y2 y2228
#define rank rank228
using ll = long long;
using ld = long double; 
const string FILENAME = "input";
 
int k, n;
map<int, vector<int>> ind;

struct three {
	ll first;
	ll second;
	ll third;
	
	bool operator < (three oth) const {
		return first > oth.first;
	}
};

int main() {
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	//read(FILENAME);
	cin >> k >> n;
	ll add = 0;
	vector<pair<int, int>> v;
	vector<int> points;
	int cnt = 0;
	for (int i = 1; i <= n; i++) {
		char p, q;
		int s, t;
		cin >> p >> s >> q >> t;
		if (p == q) {
			add += abs(s - t);
		} else {
			points.pb(s);
			points.pb(t);
			if (p == '1') {
				swap(s, t);
			}
			v.pb(mp(s, t));
			cnt++;
		}
	}
	sort(all(points));		
	if (k == 1) {
		auto f = [&](int bridge) {
			ll res = 0;
			for (auto i: points) {
				res += abs(i - bridge);
			}
			res += cnt;
			return res;
		};
		
		int med = (sz(points) + 1) / 2;
		cout << f(points[med - 1]) + add << '\n';
	} else {
		auto f = [&](int i, int j) {
			ll res = 0;
			for (auto x: v) {
				res += min(abs(x.first - i) + abs(x.second - i), abs(x.first - j) + abs(x.second - j));
			}
			res += cnt;
			return res;
		};
		vector<int> bridges = points;
		for (int i = 0; i + 1 < sz(points); i++) {
			bridges.pb((points[i] + points[i + 1]) / 2);
		}
		ll ans = 1e18;
		for (auto i: bridges) {
			for (auto j: bridges) {
				chkmin(ans, f(i, j));
			}
		}
		cout << ans + add << '\n';
		return 0;
		sort(all(v));
		ll sum = 0;
		for (auto i: v) {
			sum += abs(i.second - i.first);
		}
		for (auto i: v) {
			ind[max(i.first, i.second)].pb(min(i.first, i.second));
		}
		points.resize(unique(all(points)) - points.begin());
		//ll ans = 1e18;
		for (int i = 0; i + 1 < sz(points); i++) {
			ll cost = sum;
			priority_queue<three> pq;
			int offset = 0;
			ll inpq = 2 * (points[i + 1] - points[i]); 
			for (int j = i + 1; j < sz(points); j++) {
				while (!pq.empty() && -pq.top().first <= offset) {
					cost += pq.top().second;
					inpq -= pq.top().third;
					pq.pop();
				}
				for (auto kek: ind[points[j]]) {
					if (kek >= points[i]) {
						cost -= points[j] - kek;
						pq.push({-(points[j] - points[i] + kek - points[i] - points[j] + kek + offset), points[j] - points[i] + kek - points[i], points[j] - kek});
						inpq += points[j] - kek;
					}
				}
				chkmin(ans, cost + inpq);
				if (j == sz(points)) {
					break;
				}
				offset += 2 * (points[j + 1] - points[j]);
			}
		}
		cout << ans + cnt + add << '\n';
	}
	return 0;
}
/*
2 5
B 0 A 4
B 1 B 3
A 5 B 7
B 2 A 6
B 1 A 7
 
5
2
5
5
7
*/

Subtask #1
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 0 ms 348 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 348 KB Output is correct
7 Correct 1 ms 348 KB Output is correct
8 Correct 0 ms 348 KB Output is correct
9 Correct 1 ms 348 KB Output is correct
10 Correct 1 ms 348 KB Output is correct
11 Correct 1 ms 348 KB Output is correct

Subtask #2
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 348 KB Output is correct
2 Correct 0 ms 348 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 1 ms 344 KB Output is correct
5 Correct 1 ms 348 KB Output is correct
6 Correct 1 ms 344 KB Output is correct
7 Correct 1 ms 348 KB Output is correct
8 Correct 1 ms 348 KB Output is correct
9 Correct 1 ms 348 KB Output is correct
10 Correct 1 ms 348 KB Output is correct
11 Correct 1 ms 348 KB Output is correct
12 Correct 15 ms 2244 KB Output is correct
13 Correct 38 ms 2032 KB Output is correct
14 Correct 25 ms 1996 KB Output is correct
15 Correct 19 ms 1488 KB Output is correct
16 Correct 20 ms 2244 KB Output is correct
17 Correct 22 ms 2080 KB Output is correct
18 Correct 26 ms 2000 KB Output is correct
19 Correct 31 ms 2032 KB Output is correct
20 Correct 20 ms 2244 KB Output is correct
21 Correct 27 ms 2248 KB Output is correct

Subtask #3
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 348 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 32.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 344 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #5
0 / 37.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 348 KB Output isn't correct
2 Halted 0 ms 0 KB -