제출 #91535

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
91535		SOIVIEONE	Bank (IZhO14_bank)	C++14	44 / 100	1070 ms	126580 KiB

bank

#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>

#define INF 1000000021
#define MOD 1000000007
#define pb push_back
#define sqr(a) (a)*(a)
#define M(a, b) make_pair(a,b)
#define T(a, b, c) make_pair(a, make_pair(b, c))
#define F first
#define S second
#define all(x) (x.begin(), x.end())
#define deb(x) cerr << #x << " = " << x << '\n'
#define N 222222

using namespace std;
//using namespace __gnu_pbds;

typedef long double ld;
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
//typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> indexed_set;

const ld pi = 2 * acos(0.0);
template<class T> bool umin(T& a, T b){if(a>b){a=b;return 1;}return 0;}
template<class T> bool umax(T& a, T b){if(a<b){a=b;return 1;}return 0;}
template<class T, class TT> bool pal(T a, TT n){int k=0;for(int i=0;i<=n/2;i++){if(a[i]!=a[n-i-1]){k=1;break;}}return k?0:1;}

//int month[] = {0,31,28,31,30,31,30,31,31,30,31,30,31};

ll a[N], b[N];
int n, m;
map<pair<int, vi>, int> mp;
void f(int id, vector<int> v)
{
	if(id == m)
	{
		for(int i = 1; i <= n; i ++)
		{
			if(v[i] != a[i])
				return;
		}
		cout << "YES\n";
		exit(0);
	}
	if(mp.count(M(id, v)))
		return;
	for(int i = 1; i <= n; i ++)
	{
		v[i] += b[id];
      if(v[i]<=a[i])
		f(id+1, v);
		v[i] -= b[id];
	}
	f(id+1,v);
	mp[M(id, v)] = 1;
}

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cin >> n >> m;
	for(int i = 1; i <= n; i ++)
		cin >> a[i];
	for(int i = 0; i < m; i ++)
		cin >> b[i];
	vi v(n+1,0);
	f(0, v);
	cout << "NO";

	





	getchar();
	getchar();
	return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

bank.cpp: In function 'void f(int, std::vector<int>)':
bank.cpp:54:7: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
       if(v[i]<=a[i])
       ^~
bank.cpp:56:3: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
   v[i] -= b[id];
   ^

• Subtask 1: 19 / 19
• Subtask 2: 25 / 25
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29