제출 #914619

#제출 시각아이디문제언어결과실행 시간메모리
914619goodspeed0208Group Photo (JOI21_ho_t3)C++14
100 / 100
648 ms393348 KiB
#include<iostream>
#include<vector>
#include<algorithm>
#include<utility>
#define INF 10000000000000000
#define int long long 
using namespace std;

signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	int n;
	cin >> n;
	vector<int>v(n+5);
	vector<int>pos(n+5);
	//vector<vector<int> >arr(n+5, vector<int>(n+5));
	for (int i = 1 ; i <= n ; i++) {
		cin >> v[i];
		pos[v[i]] = i;
	}
	vector<vector<int> >front(n+5, vector<int>(n+5, 0));
	//" front[i][j] -> 1~j有幾個在i前"
	for (int i = 1 ; i<= n ; i++) {
		front[i][0] = 0;
		for (int j = 1 ; j <= n ; j++) {
			if (pos[j] < pos[i]) front[i][j] = front[i][j-1] + 1;
			else front[i][j] = front[i][j-1];
		}
	}
	vector<int>dp(n, INF);
	vector<vector<int> >cost(n+5, vector<int>(n+5));
	//cost(i-1, j) :[... ][j ...] [ i-1 i-2 ... j+1] ...
	//cost(i, j)  : [... ][j ...] [ i   i-1 ... j+1] ...
	//cost(i+1, j): [... ][j ...] [ i+1 i   ... j+1] ...
	//"cost[i+1][j] = cost[i][j] + (j+1~n 在i+1前) - (j+1~i 在i+1後) "// i > j
	                           
	//"cost[i][j] = cost[i-1][j] + (j+1~n 在i前) - (j+1~i-1 在i後) "// i > j
	vector<int>ans(n+5, INF);
	ans[0] = 0;          
	for (int j = 0 ; j <= n ; j++) {
		//cost[i][0] = 0;
		cost[j+1][j] = ans[j] + (front[j+1][n] - front[j+1][j]);
		ans[j+1] = min(ans[j+1], cost[j+1][j]);
		//cout << j << " " << ans[j] << "\n";
		//cout << j+1 << " " << j << " " << cost[j+1][j] << "\n";
		for (int i = j+2 ; i <= n ; i++) {
			// j j-1 ... [i i-1 ... j+1]
			cost[i][j] = cost[i-1][j] + (front[i][n] - front[i][j]) - ((i-j-1) - (front[i][i-1] - front[i][j]) );
			ans[i] = min(ans[i], cost[i][j]);
			//cout << i << " " << j << " " << cost[i][j] << "\n";
		}
	}
	cout << ans[n] << "\n";
	for (int i = 1 ; i <= n ; i++) {
		for (int j = 0 ; j < i ; j++) {
			dp[i] = min(dp[i], dp[j] + cost[i][j]);
		}
	}
	
}













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