| # | Time | Username | Problem | Language | Result | Execution time | Memory |
|---|---|---|---|---|---|---|---|
| 914099 | Alphanumeric | Coreputer (IOI23_coreputer) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
/*
⣿⣿⡿⣫⣾⠏⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⢀⣀⣀⣀⣀⠄⠄⠄⠄⠄⠄
⣿⡇⠱⠉⠁⠄⠄⠄⠄⠄⠄⢀⣀⣤⣶⣶⣿⣿⣿⣿⣿⣿⣿⣦⠄⠄⠄⠄⠄
⣿⡇⠄⠄⠄⠄⠄⢀⣠⣛⡩⣩⣭⡹⣿⣿⣿⣿⠞⣛⣛⣛⡲⣿⡇⠄⠄⠄⠄
⣿⡇⠄⠄⠄⡾⣡⣾⣿⣷⣹⣿⣿⡿⣪⡻⠟⣱⣿⣿⣿⣿⣿⣷⡹⠄⠄⠄⠄
⣿⡇⠄⠄⣼⡇⣿⣻⣿⠟⡛⢿⣿⣾⣿⡇⢰⣍⢻⡿⠛⢿⣿⡭⣿⣷⠄⠄⠄
⣿⣧⣄⡀⣿⡇⣮⣽⣿⣮⣉⣾⣿⣿⣿⣇⡸⣿⣿⣆⠛⣰⣿⣾⡿⣿⠄⠄⠄
⣿⣇⡼⣄⣿⣿⡄⠙⢿⣏⣿⣿⡮⠁⣉⣾⣷⡈⠃⢿⣿⣬⡭⠝⣀⣿⠄⠄⠐
⡆⡇⣹⣿⣿⣿⣿⡿⠓⠛⣉⣉⣉⣉⣙⣛⠓⠾⣟⢿⣿⣿⣿⣿⣿⣿⣿⠇⠄⠙
⠁⡇⣞⣿⡿⠋⠁⠄⠄⠈⠉⠙⠛⠛⠻⠿⠿⠿⣶⣌⠻⣿⣿⣿⣿⣿⢗⢴⣆⢣
⠸⣇⡻⠈⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠄⠈⢻⣷⡌⢿⣿⣿⣿⢸⠼⣣⣾
⣦⡀⠄⠄⠄⠄⠄⠄⠄⠄⠄⢀⠄⠄⠄⠄⠄⠄⠄⠄⠙⠛⠈⣿⡫⡼⢠⣾⣿⣿
⣿⣇⠄⣀⣠⡀⠄⠄⠴⠾⠿⠿⠶⠶⣦⣤⡀⠄⠄⠄⠄⠄⠄⢨⠯⢁⣿⣿⣿⣿
⣿⣿⣦⢒⠤⣅⡶⣶⣶⣾⣿⣿⣿⣷⣶⣮⣍⠢⠄⠄⠄⠄⠄⠐⢠⣾⣿⣿⣿⣿
⣿⣿⣿⣧⡐⠫⣉⡿⣬⡞⢿⣿⢯⠽⣶⡽⢟⣛⢖⣨⣛⠛⢃⣴⣿⣿⣿⣿⣿⣿
*/
// beichen is a classic problem in china
// map<pair<int,pair<int,int>>,priority_queue<pair<int, pair<int,int>>, vector<pair<int, pair<int,int>>>, greater<pair<int, pair<int,int>>>>> m;
// ^^ useless ds for good luck
#include "coreputer.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2,bmi,bmi2,lzworks,popworks")
using namespace std;
#define int long long
#define inp(arr) \
for (auto &it : arr) cin >> it;
#define outp(arr) \
for (auto it : arr) cout << it << " ";
#define inppair(arr) \
for (pair<int, int> & it : arr) cin >> it.first >> it.second;
#define outppair(arr) \
for (pair<int, int> it : arr) cout << it.first << " " << it.second << "\n";
#define for0(n) for (int i = 0; i < n; ++i)
#define for0j(n) for (int j = 0; j < n; ++j)
#define for0k(n) for (int k = 0; k < n; ++k)
#define for1(n) for (int i = 1; i <= n; ++i)
#define for1j(n) for (int j = 1; j <= n; ++j)
#define for1k(n) for (int k = 1; k <= n; ++k)
#define for1b(n) for (int i = n; i > 0; --i)
#define for1bj(n) for (int j = n; j > 0; --j)
#define for0b(n) for (int i = n - 1; i >= 0; --i)
#define for0bj(n) for (int j = n - 1; j >= 0; --j)
#define forself(start, end) for (int i = start; i < end; ++i)
#define vecall(v) v.begin(), v.end()
#define srt(arr) sort(arr, arr + (sizeof(arr) / sizeof(arr[0])))
#define srtvc(arr) sort(arr.begin(), arr.end())
#define bcsrt(arr) sort(arr, arr + (sizeof(arr) / sizeof(arr[0])), greater<int>())
#define bcsrtvc(arr) sort(arr.begin(), arr.end(), greater<int>())
#define pub push_back
#define puf push_front
#define pob pop_back
#define pof pop_front
#define pq priority_queue
#define pii pair<int, int>
#define bkpqi priority_queue<int, vector<int>, greater<int>>
#define bkpqpii priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>>
#define setzero(arr) memset(arr, 0, sizeof(arr));
#define setone(arr) memset(arr, 1, sizeof(arr));
#define setneg(arr) memset(arr, -1, sizeof(arr));
const int mod1 = 998244353;
const int mod2 = 1000000007;
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update>
vector<int> malfunctioning_cores(int n) {
vector<int> a(n, 0);
bool even = 0;
int l = 0, r = n - 1;
while (l + 1 < r) {
vector<int> v;
int mid = (l + r) / 2;
for0(mid + 1) {
v.pub(i);
}
int temp = run_diagnostic(v);
if (temp == 0) {
even = 1;
}
if (temp >= 0) {
r = mid;
} else {
l = mid;
}
}
if (l == 0) {
if (!even) {
a[0] = 1;
return a;
}
vector<int> temp;
temp.pub(0);
a[0] = 1;
for (int i = 1; i < n - 1; i++) {
temp.pub(i);
int t = run_diagnostic(temp);
if (t == 1) {
a[i] = 1;
return a;
}
temp.pob();
}
a[n - 1] = 1;
return a;
}
a[l] = 1;
int tot = 1;
vector<int> temp;
for (int i = 0; i <= l - (!even); i++) {
temp.pb(i);
}
for (int i = l + 1; i < n; i++) {
temp.pb(i);
int temp = run_diagnostic(temp);
if (temp == 1) {
a[i] = 1;
tot++;
}
temp.pob();
}
temp.clear();
for (int i = l + 1; i < n; i++) {
temp.pb(i);
}
for (int i = 1; i < l; i++) {
temp.pub(i);
int temp = run_diagnostic(temp);
if (temp == 1) {
a[i] = 1;
tot++;
}
temp.pob();
}
if (tot % 2 == even) {
a[0] = 1;
}
return a;
}