이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//Bismillahir-Rahmanir-Rahim
#include <bits/stdc++.h>
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops")
//#pragma GCC target("sse,sse2,sse3,sse4,sse4.1,sse4.2,popcnt,avx,avx2")
#define pb push_back
#define pii pair <int, int>
#define pll pair <long long, long long>
#define pld pair <long double, long double>
#define ll long long
#define ld long double
#define x first
#define y second
#define all(v) v.begin(),v.end()
#define sz(s) (int)s.size()
#define skip continue
#define bpop(x) (ll)__builtin_popcountll(x)
using namespace std;
const int N = 5e3 + 7;
const int K = 400;
const int maxA = 1e7 + 7;
const int inf = 1e9 + 7;
const ll INF = 1e18 + 7;
const ll MOD = 998244353;
const ld eps = 1e-9;
pii dir[] = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}};
//mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int n, R;
pii a[N], cur[N], slope[N];
ld dist(pii x, pii O) {
return sqrt(1.0L * (x.x - O.x) * (x.x - O.x) + 1.0L * (x.y - O.y) * (x.y - O.y));
}
void solve() {
cin >> n >> R;
for (int i = 1;i <= n;i++)cin >> a[i].x >> a[i].y >> slope[i].x >> slope[i].y, slope[i].x -= a[i].x, slope[i].y -= a[i].y, cur[i] = a[i];
int ans = 0;
for (int t = 1;t <= 2e4;t++) {
int cnt = 0;
for (int i = 1;i <= n;i++) {
if (dist(cur[i], {0, 0}) <= R)cnt++;
}
ans = max(ans, cnt);
for (int i = 1;i <= n;i++)cur[i].x += slope[i].x, cur[i].y += slope[i].y;
}
cout << ans;
}
signed main() {
//srand(time(NULL));
ios_base::sync_with_stdio(0);
cin.tie(0);
//freopen("tests.in", "r", stdin);
//freopen("milkorder.out", "w", stdout);
int test = 1;
//cin >> test;
for (int t = 1;t <= test;t++) {
//cout << "Case " << t << ": ";
solve();
}
return 0;
}
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