제출 #911198

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
911198		daoquanglinh2007	"The Lyuboyn" code (IZhO19_lyuboyn)	C++17	83 / 100	214 ms	8644 KiB

lyuboyn

#include <bits/stdc++.h>
using namespace std;

#define flipbit(x, i) x ^= (1<<(i))

const int a[] = {0, 7, 9, 2, 5, 8, 3, 4, 10, 1, 6, 11, 12, 16, 23, 13, 17, 22, 15, 19, 20, 14, 18, 21, 24, 31, 39, 32, 43, 25, 30, 38, 33, 42, 27, 28, 36, 35, 40, 26, 29, 37, 34, 41, 46, 50, 53, 44, 48, 55, 45, 49, 54, 59, 60, 47, 57, 62, 51, 61, 58, 52, 63, 56};
const int b[] = {0, 1, 3, 2, 6, 7, 5, 4};

string bS;
int N, K, S, T;
vector <int> v, ans;
int cnt[262144];

vector <int> build(int N){
	if (N == 1){
		vector <int> ans = {0, 1};
		return ans;
	}
	vector <int> a = build(N-1);
	for (int i = 0; i < (1<<(N-1)); i++){
		a.push_back((1<<(N-1))+a[(1<<(N-1))-1-i]);
	}
	return a;
}

void show(int x){
	for (int i = N-1; i >= 0; i--)
		cout << ((x>>i)&1);
	cout << endl;
}

vector <int> build3(int N){
	if (N == 6){
		vector <int> ans(0);
		for (int i = 0; i < 64; i++) ans.push_back(a[i]);
		return ans;
	}
	vector <int> tmp = build3(N-3), ans = tmp;
	for (int i = 1; i < 8; i++){
		int x = ans.back()&((1<<(N-3))-1);
		x ^= (1<<(N-4))+(1<<(N-5));
		for (int j = 0; j < (1<<(N-3)); j++)
			ans.push_back((b[i]<<(N-3))+(x^tmp[j]));
	}
	return ans;
}

int main(){
//	freopen("LYUBOYN.inp", "r", stdin);
//	freopen("LYUBOYN.out", "w", stdout);
	ios_base::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	
	cin >> N >> K >> T >> bS;
	for (int i = 0; i < N; i++)
		if (bS[i] == '1') S += (1<<(N-1-i));
		
	v = build(N);
	ans.clear();
	ans.push_back(S);
	for (int i = 1; i < (1<<N); i++){
		ans.push_back(ans[i-1]);
		for (int j = 0; j < N; j++)
			if (((v[i]^v[i-1])>>j)&1){
				for (int t = 0; t < K; t++)
					flipbit(ans[i], (j+t)%N);
			}
	}
	bool ok = 1;
	for (int x : ans){
		if (cnt[x]){
			ok = 0;
			break;
		}
		cnt[x]++;
	}
	if (ok){
		cout << (1<<N) << '\n';
		for (int x : ans){
			for (int i = N-1; i >= 0; i--)
				cout << ((x>>i)&1);
			cout << '\n';
		}
		return 0;
	}
	if (K != 3 || N == 3){
		if (N == 10 && K == 5){
			cout << "MMB" << endl;
		}
		cout << "-1\n";
		return 0;
	}
	ans = build3(N);
	cout << (1<<N) << '\n';
	for (int &x : ans){
		x ^= S;
		for (int i = N-1; i >= 0; i--)
			cout << ((x>>i)&1);
		cout << '\n';
	}
	return 0;
}

• Subtask 1: 0 / 0
• Subtask 2: 5 / 5
• Subtask 3: 3 / 3
• Subtask 4: 11 / 11
• Subtask 5: 15 / 15
• Subtask 6: 18 / 18
• Subtask 7: 31 / 31
• Subtask 8: 0 / 17