This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define flipbit(x, i) x ^= (1<<(i))
const int a[] = {0, 7, 9, 2, 5, 8, 3, 4, 10, 1, 6, 11, 12, 16, 23, 13, 17, 22, 15, 19, 20, 14, 18, 21, 24, 31, 39, 32, 43, 25, 30, 38, 33, 42, 27, 28, 36, 35, 40, 26, 29, 37, 34, 41, 46, 50, 53, 44, 48, 55, 45, 49, 54, 59, 60, 47, 57, 62, 51, 61, 58, 52, 63, 56};
const int b[] = {0, 1, 3, 2, 6, 7, 5, 4};
string bS;
int N, K, S, T;
vector <int> v, ans;
int cnt[262144];
vector <int> build(int N){
if (N == 1){
vector <int> ans = {0, 1};
return ans;
}
vector <int> a = build(N-1);
for (int i = 0; i < (1<<(N-1)); i++){
a.push_back((1<<(N-1))+a[(1<<(N-1))-1-i]);
}
return a;
}
void show(int x){
for (int i = N-1; i >= 0; i--)
cout << ((x>>i)&1);
cout << endl;
}
vector <int> build3(int N){
if (N == 6){
vector <int> ans(0);
for (int i = 0; i < 64; i++) ans.push_back(a[i]);
return ans;
}
vector <int> tmp = build3(N-3), ans = tmp;
for (int i = 1; i < 8; i++){
int x = ans.back()&((1<<(N-3))-1);
x ^= (1<<(N-4))+(1<<(N-5));
for (int j = 0; j < (1<<(N-3)); j++)
ans.push_back((b[i]<<(N-3))+(x^tmp[j]));
}
return ans;
}
int main(){
// freopen("LYUBOYN.inp", "r", stdin);
// freopen("LYUBOYN.out", "w", stdout);
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> N >> K >> T >> bS;
for (int i = 0; i < N; i++)
if (bS[i] == '1') S += (1<<(N-1-i));
v = build(N);
ans.clear();
ans.push_back(S);
for (int i = 1; i < (1<<N); i++){
ans.push_back(ans[i-1]);
for (int j = 0; j < N; j++)
if (((v[i]^v[i-1])>>j)&1){
for (int t = 0; t < K; t++)
flipbit(ans[i], (j+t)%N);
}
}
bool ok = 1;
for (int x : ans){
if (cnt[x]){
ok = 0;
break;
}
cnt[x]++;
}
if (ok){
cout << (1<<N) << '\n';
for (int x : ans){
for (int i = N-1; i >= 0; i--)
cout << ((x>>i)&1);
cout << '\n';
}
return 0;
}
if (K != 3 || N == 3){
if (K == 5){
cout << "MMB" << endl;
}
cout << "-1\n";
return 0;
}
ans = build3(N);
cout << (1<<N) << '\n';
for (int &x : ans){
x ^= S;
for (int i = N-1; i >= 0; i--)
cout << ((x>>i)&1);
cout << '\n';
}
return 0;
}
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