Submission #908739

#	Time	Username	Problem	Language	Result	Execution time	Memory
908739		Nelt	Exam (eJOI20_exam)	C++17	0 / 100	1075 ms	2392 KiB

exam

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx,avx2,fma,popcnt")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

/* DEFINES */
#define S second
#define F first
#define ll long long
#define ull unsigned long long
#define ld long double
#define npos ULLONG_MAX
#define INF LLONG_MAX
#define vv(a) vector<a>
#define ss(a) set<a>
#define pp(a, b) pair<a, b>
#define mm(a, b) map<a, b>
#define qq(a) queue<a>
#define pq(a) priority_queue<a>
#define ump(a, b) unordered_map<a, b>
#define ANDROID                   \
    ios_base::sync_with_stdio(0); \
    cin.tie(0);                   \
    cout.tie(0);
#define allc(a) begin(a), end(a)
#define all(a) a, a + sizeof(a) / sizeof(a[0])
#define elif else if
#define endl "\n"
#define pb push_back
#define ins insert
#define logi __lg
#define sqrt sqrtl
#define mpr make_pair
using namespace std;
using namespace __cxx11;
using namespace __gnu_pbds;
typedef char chr;
typedef basic_string<chr> str;
template <typename T, typename key = less<T>>
using ordered_set = tree<T, null_type, key, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

void solve()
{
    ll n;
    cin >> n;
    ll dp[n + 1];
    ll a[n + 1], b[n + 1];
    for (ll i = 1; i <= n; i++)
        cin >> a[i];
    for (ll i = 1; i <= n; i++)
        cin >> b[i];
    mm(ll, ll) mp;
    dp[0] = 0;
    for (ll i = 1; i <= n; i++)
    {
        dp[i] = dp[i - 1];
        mp.clear();
        for (ll j = i, mx = 0; j >= 1; j--)
            mp[b[j]]++, mx = max(mx, a[j]), dp[i] = max(dp[i], dp[j - 1] + (mp.count(mx) ? mp[mx] : 0));
    }
    cout << dp[n] << endl;
}
/*

*/
int main()
{
    ANDROID
    // precomp();
    ll t = 1;
    // cin >> t;
    for (ll i = 1; i <= t; i++)
        // cout << "Case #" << i << ": ",
        solve();
    cerr << "\nTime elapsed : " << clock() * 1000.0 / CLOCKS_PER_SEC << " ms\n";
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 12
• Subtask 3: 0 / 13
• Subtask 4: 0 / 23
• Subtask 5: 0 / 16
• Subtask 6: 0 / 22