This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "coreputer.h"
#include <bits/stdc++.h>
using namespace std;
vector<int> ntwo(){
int res = run_diagnostic({0});
if (res == 1){
return {1, 0};
}
else if (res == 0){
int any = run_diagnostic({0, 1});
if (any == 0){
return {0, 0};
}
else return {1, 1};
}
else return {0, 1};
}
vector<int> malfunctioning_cores(int N) {
if (N == 2){
return ntwo();
}
//if malfunctioning cores is even
int results[N];
for (int x = 0; x < N; x++){
vector<int> bruh;
for (int y = 0; y <= x; y++) bruh.push_back(y);
results[x] = run_diagnostic(bruh);
}
int firstZero = -1, lastZero = -1;
for (int x = 0; x < N; x++){
if (results[x] == 0){
if (firstZero == -1) firstZero = x;
lastZero = x;
}
}
assert(lastZero != -1); //even case
assert(firstZero != -1);
//cerr << firstZero << ' ' << lastZero << '\n';
//our malfunctions are at firstZero, and lastZero+1
//we also now know that there are an equal number of malfunctions in the two segments [0, firstZero-1] and [lastZero+2, 15]
vector<int> ans(N, 0);
ans[firstZero] = 1;
ans[lastZero+1] = 1;
for (int x = N-1; x > lastZero+1; x--){
//include [0, firstZero], include [lastZero+1, 15], except one element
vector<int> cur;
#define ADDRANGE(a, b) for (int y = a; y <= b; y++) cur.push_back(y);
ADDRANGE(0, firstZero);
//ADDRANGE(lastZero+1, 15);
//cur.erase(find(cur.begin(), cur.end(), x));
ADDRANGE(x, x);
int res = run_diagnostic(cur);
//cerr << "\n run: \n";
//for (auto y : cur) cerr << y << ' ';
//cerr << '\n';
//cerr << res << '\n';
if (res == 0){
ans[x] = 0;
}
else ans[x] = 1;
}
for (int x = 0; x < firstZero; x++){
//include [0, firstZero], exclude [lastZero+1, 15], except one element
vector<int> cur;
#define ADDRANGE(a, b) for (int y = a; y <= b; y++) cur.push_back(y);
//ADDRANGE(0, firstZero);
ADDRANGE(lastZero+1, N-1);
ADDRANGE(x, x);
//cur.erase(find(cur.begin(), cur.end(), x));
int res = run_diagnostic(cur);
if (res == 0){
ans[x] = 0;
}
else ans[x] = 1;
}
return ans;
}
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