Submission #907012

#	Time	Username	Problem	Language	Result	Execution time	Memory
907012		gaga999	Sandcastle 2 (JOI22_ho_t5)	C++17	15 / 100	5064 ms	20320 KiB

Main

#include <cstdio>
#include <stdio.h>
#include <iostream>
#include <math.h>
#include <vector>
#include <queue>
#include <stack>
#include <deque>
#include <algorithm>
#include <utility>
#include <set>
#include <map>
#include <stdlib.h>
#include <cstring>
#include <string.h>
#include <string>
#include <sstream>
#include <assert.h>
#include <climits>
#include <sstream>
#include <numeric>
#include <time.h>
#include <limits.h>
#include <list>
#include <bitset>
#include <unordered_map>
#include <unordered_set>
#include <random>
#include <iomanip>
#include <complex>
#include <chrono>
#include <fstream>
#include <functional>
#include <unistd.h>
// #pragma GCC optimize("Ofast,no-stack-protector")
// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx,avx2,bmi,bmi2,lzcnt,popcnt")
#define lowbit(x) ((x) & -(x))
#define ml(a, b) ((1ll * (a) * (b)) % M)
#define tml(a, b) (a) = ((1ll * (a) * (b)) % M)
#define ad(a, b) ((0ll + (a) + (b)) % M)
#define tad(a, b) (a) = ((0ll + (a) + (b)) % M)
#define mi(a, b) ((0ll + M + (a) - (b)) % M)
#define tmi(a, b) (a) = ((0ll + M + (a) - (b)) % M)
#define tmin(a, b) (a) = min((a), (b))
#define tmax(a, b) (a) = max((a), (b))
#define iter(a) (a).begin(), (a).end()
#define riter(a) (a).rbegin(), (a).rend()
#define init(a, b) memset((a), (b), sizeof(a))
#define cpy(a, b) memcpy((a), (b), sizeof(a))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define pb emplace_back
#define mpr make_pair
#define ls(i) ((i) << 1)
#define rs(i) ((i) << 1 | 1)
#define INF 0x3f3f3f3f
#define NIF 0xc0c0c0c0
#define eps 1e-9
#define F first
#define S second
#define AC cin.tie(0)->sync_with_stdio(0)
using namespace std;
typedef long long llt;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<llt, llt> pll;
typedef complex<double> cd;
// const int M = 998244353;

// random_device rm;
// mt19937 rg(rm());
// default_random_engine rg(rm());
// uniform_int_distribution<int> rd(INT_MIN, INT_MAX);
// uniform_real_distribution<double> rd(0, M_PI);

void db() { cerr << "\n"; }
template <class T, class... U>
void db(T a, U... b) { cerr << a << " ", db(b...); }

inline char gc()
{
    const static int SZ = 1 << 16;
    static char buf[SZ], *p1, *p2;
    if (p1 == p2 && (p2 = buf + fread(p1 = buf, 1, SZ, stdin), p1 == p2))
        return -1;
    return *p1++;
}
void rd() {}
template <typename T, typename... U>
void rd(T &x, U &...y)
{
    x = 0;
    bool f = 0;
    char c = gc();
    while (!isdigit(c))
        f ^= !(c ^ 45), c = gc();
    while (isdigit(c))
        x = (x << 1) + (x << 3) + (c ^ 48), c = gc();
    f && (x = -x), rd(y...);
}

template <typename T>
void prt(T x)
{
    if (x < 0)
        putchar('-'), x = -x;
    if (x > 9)
        prt(x / 10);
    putchar((x % 10) ^ 48);
}

vector<vector<int>> gd, v[3][3][3][3], v1[3][3], v2[3][3], vr;
#define p1 [x - 1][y]
#define p2 [x][y - 1]
#define p3 [x][y + 1]
#define p4 [x + 1][y]
#define c1 x != l
#define c2 y != u
#define c3 y != d
#define c4 x != r
int gv(int x, int y, int l, int r, int u, int d)
{
    int mn = INF, cr = gd[x][y], res = 0;
    if (c1 && gd p1 > cr && gd p1 < mn)
        mn = gd p1, res = 1;
    if (c2 && gd p2 > cr && gd p2 < mn)
        mn = gd p2, res = 2;
    if (c3 && gd p3 > cr && gd p3 < mn)
        mn = gd p3, res = 3;
    if (c4 && gd p4 > cr && gd p4 < mn)
        mn = gd p4, res = 4;
    return res;
}
#define pp l, r, u, d
int slv(int x, int y, int l, int r, int u, int d)
{
    int res = 0;
    if (c1 && gv(x - 1, y, pp) == 4)
        res++;
    if (c2 && gv(x, y - 1, pp) == 3)
        res++;
    if (c3 && gv(x, y + 1, pp) == 2)
        res++;
    if (c4 && gv(x + 1, y, pp) == 1)
        res++;
    return !res;
}
inline int grc(int l, int r, int i, int j)
{
    return vr[l][i] + vr[r][j] - vr[l][j] - vr[r][i];
}
#define vt(i, j) vector<vector<int>>(i, vector<int>(j))
signed main()
{
    int n, m;
    rd(n, m);
    if (n > m)
    {
        swap(n, m);
        gd = vt(n, m);
        for (int i = 0; i < m; i++)
            for (int j = 0; j < n; j++)
                rd(gd[j][i]);
    }
    else
    {
        gd = vt(n, m);
        for (int i = 0; i < n; i++)
            for (int j = 0; j < m; j++)
                rd(gd[i][j]);
    }
    for (int l = 0; l < 3; l++)
    {
        for (int r = 0; r < 3; r++)
        {
            for (int u = 0; u < 3; u++)
            {
                for (int d = 0; d < 3; d++)
                {
                    v[l][r][u][d] = vt(n, m);
                    for (int i = 0; i < n; i++)
                        for (int j = 0; j < m; j++)
                            v[l][r][u][d][i][j] =
                                slv(i, j, max(0, i - l), min(n - 1, i + r), max(0, j - u), min(m - 1, j + d));
                }
            }
        }
    }
    for (int l = 0; l < 3; l++)
    {
        for (int r = 0; r < 3; r++)
        {
            v1[l][r] = v2[l][r] = vt(n, m);
            for (int i = 0; i < n; i++)
            {
                v1[l][r][i][0] = v[l][r][2][2][i][0];
                for (int j = 1; j < m; j++)
                    v1[l][r][i][j] = v[l][r][2][2][i][j] + v1[l][r][i][j - 1];
            }
            for (int j = 0; j < m; j++)
            {
                v2[l][r][0][j] = v[2][2][l][r][0][j];
                for (int i = 1; i < n; i++)
                    v2[l][r][i][j] = v[2][2][l][r][i][j] + v2[l][r][i - 1][j];
            }
        }
    }
    vr = vt(n, m);
    for (int i = 0; i < m; i++)
        vr[0][i] = v[2][2][2][2][0][i];
    for (int i = 1; i < n; i++)
    {
        vr[i][0] = v[2][2][2][2][0][i];
        for (int j = 1; j < m; j++)
        {
            vr[i][j] = vr[i - 1][j] + vr[i][j - 1] -
                       vr[i - 1][j - 1] + v[2][2][2][2][i][j];
        }
    }
    llt ans = 0;
    for (int l = 0; l < n; l++)
    {
        for (int r = 0; r < n; r++)
        {
            for (int i = 0; i < m; i++)
            {
                for (int j = i; j < m; j++)
                {
                    int tp = 0;
                    for (int a = l; a <= r; a++)
                        for (int b = i; b <= j; b++)
                            tp += v[min(2, a - l)][min(2, r - a)][min(2, b - i)][min(2, j - b)][a][b];
                    if (tp == 1)
                        ans++;
                }
            }
        }
    }
    prt(ans), putchar('\n');
}

• Subtask 1: 0 / 9
• Subtask 2: 10 / 10
• Subtask 3: 5 / 5
• Subtask 4: 0 / 56
• Subtask 5: 0 / 20