This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,fma,bmi,bmi2,popcnt,lzcnt")
#include<bits/stdc++.h>
#define ll int
#define pll pair<ll, ll>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ld long double
using namespace std;
const long long inf=LLONG_MAX, maxn=1e6+5;
long long cnt[maxn], to[maxn];
long long n, k, dp[maxn], pre[maxn];
struct Line
{
mutable long long k, m, p, idx;
bool operator < (const Line &o) const{return k<o.k;}
bool operator < (long long o) const {return p<o;}
};
struct CHT
{
int csz = 0;
vector <Line> data;
long long floordiv(long long a, long long b){return a/b-(((a^b)<0) && (a%b));}
long long isect(Line x, Line y) {
if (x.k == y.k) return (x.m > y.m ? inf : -inf);
return floordiv(x.m - y.m, y.k - x.k);
}
void add(long long k, long long m, ll idx)
{
k = -k, m = -m;
Line L = {k, m, inf, idx};
while (csz >= 2 and isect(data[csz - 2], data[csz - 1]) >= isect(data[csz - 1], L)) {
--csz; data.pop_back();
if (csz >= 2) data[csz - 2].p = isect(data[csz - 2], data[csz - 1]);
}
if (csz) data.back().p = isect(data.back(), L);
++csz; data.push_back(L);
}
pair<long long, ll> query(ll x)
{
auto L = *lower_bound(data.begin(), data.end(), x);
return {-L.k*x-L.m, L.idx};
}
};
pair<long long, ll> solve(long long C)
{
ll crr=1;
CHT A; A.add(0, -pre[to[0]-1], 0);
for (ll i=1; i<=n; i++)
dp[i]=inf, cnt[i]=0;
for (ll i=1; i<=n; i++)
{
while (crr<i && to[crr]<=i)
A.add(-crr, -(pre[to[crr]-1]-(to[crr]-1)*crr)+dp[crr], cnt[crr]), crr++;
tie(dp[i], cnt[i])=A.query(i);
dp[i]+=C+pre[i], cnt[i]++;
if (crr<i && dp[crr]+C<dp[i])
dp[i]=dp[crr]+C, cnt[i]=cnt[crr]+1;
}
return {dp[n], cnt[n]};
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
//freopen("input.txt", "r", stdin);
//freopen("output.txt", "w", stdout);
cin >> n >> k;
string s; cin >> s;
long long x=0, y=0, crr=1;
for (ll i=0; i<n*2; i++)
{
if (s[i]=='A')
x++, pre[x]=pre[x-1]+y;
else y++;
}
for (ll i=1; i<=n; i++)
while (crr<=pre[i]-pre[i-1])
to[crr]=i, crr++;
while (crr<=n) to[crr]=n+1, crr++;
for (ll i=0; i<=n; i++)
if (to[i]<=i)
to[i]=i+1;
long long lo=0, hi=1LL*n*n;
while (hi>lo)
{
long long mid=(lo+hi)/2;
if (solve(mid).se<=k)
hi=mid;
else lo=mid+1;
}
cout << 0LL+solve(lo).fi-lo*k;
}
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