oj.uz

답안 #897459

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
897459 2024-01-03T06:42:45 Z nightfal 전선 연결 (IOI17_wiring) C++14
25 / 100
 33 ms 4772 KB 
// #include "wiring.h"
#include <cassert>
#include <cstdio>
#include <vector>
#include <climits>
#include <stdlib.h>
#include <algorithm>

using namespace std;
 
bool isSubtask1(std::vector<int> r, std::vector<int> b) {return r.size()<=200 && b.size()<=200;}
bool isSubtask2(std::vector<int> r, std::vector<int> b) {return r[r.size()-1]<b[0];}
bool isSubtask3(std::vector<int> r, std::vector<int> b) {
    int n=r.size(), m=b.size();
    vector<int> a(n+m);
   
    for(int i=0, j=0; i<n || j<m;)
        i==n? a[i+j++]=1: j==m? a[j+i++]=0: r[i]<b[j]? a[j+i++]=0:a[i+j++] = 1;

    int cnt = 1;
    for(int k=1; k<n+m; k++) {
        cnt = a[k]==a[k-1]? cnt+1:0;
        if (cnt > 6) return false;
    }
  return true;
}
bool isSubtask4(std::vector<int> r, std::vector<int> b) {
    return min(r[0],b[0])==1 && max(r[r.size()-1],b[b.size()-1])==r.size()+b.size();
}
 
long long subtask1(std::vector<int>, std::vector<int>);
long long subtask2(std::vector<int> &, std::vector<int> &, int, int, int, int);
long long subtask3(std::vector<int>, std::vector<int>);
long long subtask4(std::vector<int>, std::vector<int>);
long long min_total_length(std::vector<int>, std::vector<int> );


 
long long min_total_length(std::vector<int> r, std::vector<int> b) {
    // if (isSubtask4(r,b)) return subtask4(r,b);
    return subtask4(r,b);
    if (isSubtask3(r,b)) return subtask3(r,b);
  	else if (isSubtask2(r,b)) return subtask2(r,b,0,r.size()-1,0,b.size()-1);    
  	else if (isSubtask1(r,b)) return subtask1(r,b);
//     else return fullTask(r,b);
    return 0;
}

long long subtask4(std::vector<int> r, std::vector<int> b) {
    int n = r.size(), m = b.size();
    vector<int> a(n+m);
    
    for(int i=0, j=0; i<n || j<m;)
        i==n? a[i+j++]=1: j==m? a[j+i++]=0: r[i]<b[j]? a[j+i++]=0: a[i+j++]=1;
    // for(int i=0; i<n+m; i++)
    //     printf("%d ", a[i]);
    // printf("\n");
    long long dp1=LLONG_MAX, dp2=LLONG_MAX;

    long long cntL=0, sumL=0, sumL2=0, cntR=1, sumR=0, sumR2=0;
    int prev=-1, curr=0; 

    for(int i=1; i<n+m; i++) {
        if (a[i]!=a[i-1]) {prev=curr; curr=i; cntL=cntR, cntR=0;}
        cntR++;
        // printf("i=%d, prev=%d, curr=%d, cntL=%d, cntR=%d\n",i,prev,curr,cntL,cntR);

        if(i==n+m-1) {
            if(prev==0) {
                sumL = cntL*(cntL-1)/2; sumR = (cntR)*(cntR-1)/2; 
                // printf("sumL=%lld, sumR=%lld, max(cntL,cntR)=%d\n",sumL,sumR,max(cntL,cntR));
                return sumL + sumR + max(cntL,cntR);
            }
            else {
                sumL = (cntL/2)*(cntL/2-1)/2; sumL2 = ((cntL+1)/2)*((cntL+1)/2-1)/2;
                sumR = (cntR)*(cntR-1)/2;
                // printf("sumL=%lld, sumL2=%lld, sumR=%lld, sumR2=%lld\n",sumL,sumL2,sumR,sumR2);
                long long dp = sumL + dp2 + sumR + max(cntL/2,cntR);
                if(dp1 < LLONG_MAX) dp = min(dp, sumL2 + dp1 + sumR + max((cntL+1)/2,cntR));
                return dp;
            }
        }
        else if (a[i]!= a[i+1]) { 
            if (prev==0) {
                sumL = cntL*(cntL-1)/2; 
                sumR = (cntR/2)*(cntR/2-1)/2; sumR2 = ((cntR+1)/2)*((cntR+1)/2-1)/2;
                if (cntR!=1) dp1 = sumL+sumR +max(cntL,cntR/2); 
                dp2 = sumL+sumR2+max(cntL,(cntR+1)/2);            
            }
            else if (prev>0) {
                sumL = (cntL/2)*(cntL/2-1)/2; sumL2 = ((cntL+1)/2)*((cntL+1)/2-1)/2;
                sumR = (cntR/2)*(cntR/2-1)/2; sumR2 = ((cntR+1)/2)*((cntR+1)/2-1)/2;
                long long new_dp1, new_dp2;
                new_dp1 = sumL + dp2 + sumR  + max(cntL/2,cntR/2); 
                new_dp2 = sumL + dp2 + sumR2 + max(cntL/2,(cntR+1)/2);
                if (dp1<LLONG_MAX) {
                    new_dp1 = min(new_dp1, sumL2 + dp1 + sumR  + max((cntL+1)/2,cntR/2));
                    new_dp2 = min(new_dp2, sumL2 + dp1 + sumR2 + max((cntL+1)/2,(cntR+1)/2));
                }
                dp1 = new_dp1; dp2 = new_dp2;
            }
            // printf("sumL=%lld, sumL2=%lld, sumR=%lld, sumR2=%lld\n",sumL,sumL2,sumR,sumR2);
            // printf("dp1=%lld, dp2=%lld\n",dp1,dp2);
        }
    }
}

long long subtask3(std::vector<int> r, std::vector<int> b) {
    int n = r.size(), m = b.size();
    vector<pair<int,int>> a(n+m);
    
    for(int i=0, j=0; i<n || j<m;) // make_pair 내부에서 ++ 하면 안됨
        i==n? a[i+j++]=make_pair(j,1): j==m? a[j+i++]=make_pair(i,0): r[i]<b[j]? a[j+i++]=make_pair(i,0): a[i+j++]=make_pair(j,1);

    vector<long long> dp(n+m,LLONG_MAX);

    long long sumL=0, cntL=0, sumR=0, cntR=0, gap=0;
    int prev=-1, curr=0;

    for(int i=1; i<n+m; i++) {
        if (a[i].second != a[i-1].second) {
            prev=curr; curr=i; sumR=cntR=0;
            gap= a[prev].second==0? b[a[curr].first]-r[a[curr-1].first]: r[a[curr].first]-b[a[curr-1].first];
        }
        if (prev==-1) continue;
        sumR += a[curr].second==0? r[a[i].first]-r[a[curr].first]:b[a[i].first]-b[a[curr].first];
        cntR++;
        for(int j=curr-1; j>=prev; j--) {
            cntL++; 
            sumL += a[prev].second==0? r[a[curr-1].first]-r[a[j].first]:b[a[curr-1].first]-b[a[j].first]; 
            long long temp = sumL + sumR + max(cntL,cntR)*gap;
            if (j!=0) {
                long long minDP = min(dp[j-1],dp[j]);        
                if (minDP >= LLONG_MAX) continue;
                else temp += min(dp[j-1],dp[j]);        
            }
            if (dp[i]>temp) dp[i]=temp;
            // printf("dp[%d,%d]=%d, sumL=%d, sumR=%d, gap=%d\n",i,j,dp[i],sumL,sumR,gap);
        }
        sumL=cntL=0;
    }
    return dp[n+m-1];
}

long long subtask2(std::vector<int> &arr1, std::vector<int> &arr2, int s1, int e1, int s2, int e2) {
  long long sum1=0, sum2=0, n = e1-s1+1, m=e2-s2+1;
  for(int i=s1; i<=e1; i++) sum1 += arr1[e1] - arr1[i];
  for(int i=s2; i<=e2; i++) sum2 += arr2[i] - arr2[s2];
  return sum1+sum2+max(n,m)*(arr2[s2]-arr1[e1]);
}

long long subtask1(std::vector<int> r, std::vector<int> b) {
	int n = r.size(), m = b.size();
    long long dp[n][m];
  	dp[0][0] = abs(r[0]-b[0]);
  	for(int i=1; i<n; i++) dp[i][0] = dp[i-1][0] + abs(r[i]-b[0]);
    for(int j=1; j<m; j++) dp[0][j] = dp[0][j-1] + abs(r[0]-b[j]);
  	for(int i=1; i<n; i++)  	
      for(int j=1; j<m; j++)
        dp[i][j] = min(min(dp[i-1][j],dp[i][j-1]),dp[i-1][j-1]) + abs(r[i]-b[j]);

	return dp[n-1][m-1];
}

Compilation message

wiring.cpp: In function 'bool isSubtask4(std::vector<int>, std::vector<int>)':
wiring.cpp:28:65: warning: comparison of integer expressions of different signedness: 'const int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   28 |     return min(r[0],b[0])==1 && max(r[r.size()-1],b[b.size()-1])==r.size()+b.size();
      |                                 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~
wiring.cpp: In function 'long long int subtask1(std::vector<int>, std::vector<int>)':
wiring.cpp:159:7: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
  159 |       for(int j=1; j<m; j++)
      |       ^~~
wiring.cpp:162:2: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
  162 |  return dp[n-1][m-1];
      |  ^~~~~~
wiring.cpp: In function 'long long int subtask4(std::vector<int>, std::vector<int>)':
wiring.cpp:51:22: warning: control reaches end of non-void function [-Wreturn-type]
   51 |     vector<int> a(n+m);
      |                      ^

Subtask #1
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 344 KB 3rd lines differ - on the 1st token, expected: '25859', found: '63'
2 Halted 0 ms 0 KB -

Subtask #2
0 / 13.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 348 KB 3rd lines differ - on the 1st token, expected: '904', found: '315'
2 Halted 0 ms 0 KB -

Subtask #3
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 344 KB 3rd lines differ - on the 1st token, expected: '316', found: '36'
2 Halted 0 ms 0 KB -

Subtask #4
25.0 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 33 ms 4636 KB Output is correct
3 Correct 27 ms 4772 KB Output is correct
4 Correct 26 ms 4700 KB Output is correct
5 Correct 26 ms 4700 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
7 Correct 0 ms 348 KB Output is correct
8 Correct 0 ms 348 KB Output is correct
9 Correct 0 ms 348 KB Output is correct
10 Correct 0 ms 348 KB Output is correct
11 Correct 1 ms 348 KB Output is correct
12 Correct 0 ms 348 KB Output is correct
13 Correct 0 ms 348 KB Output is correct
14 Correct 1 ms 344 KB Output is correct
15 Correct 0 ms 344 KB Output is correct
16 Correct 0 ms 348 KB Output is correct
17 Correct 0 ms 600 KB Output is correct
18 Correct 26 ms 4692 KB Output is correct
19 Correct 26 ms 4644 KB Output is correct
20 Correct 26 ms 4700 KB Output is correct
21 Correct 22 ms 4768 KB Output is correct
22 Correct 16 ms 4696 KB Output is correct
23 Correct 16 ms 4700 KB Output is correct
24 Correct 16 ms 4688 KB Output is correct

Subtask #5
0 / 45.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1 ms 344 KB 3rd lines differ - on the 1st token, expected: '25859', found: '63'
2 Halted 0 ms 0 KB -