제출 #893251

#제출 시각아이디문제언어결과실행 시간메모리
893251serifefedartarCopy and Paste 3 (JOI22_copypaste3)C++17
20 / 100
288 ms110416 KiB
#include <bits/stdc++.h>
using namespace std;
 
#define fast ios::sync_with_stdio(0);cin.tie(0);
typedef long long ll;
#define f first
#define s second
#define MOD 998244353
#define LOGN 21
const ll MAXN = 2550;

const ll P = 39;
ll N, A, B, C;
string s;
ll hashes[MAXN], to[MAXN][MAXN], dp[MAXN][MAXN], powP[MAXN];
ll f(int l, int r) {
    ll h = (hashes[r] - powP[r-l+1] * hashes[l - 1] % MOD) % MOD;
    if (h < 0)
        h += MOD;
    return h;
}

vector<int> occ[MAXN];
map<ll, deque<int>> mp;

int main() {
    fast
    cin >> N >> s >> A >> B >> C;
    s = "#" + s; 

    powP[0] = 1;
    for (int i = 1; i <= N; i++)
        powP[i] = (powP[i-1] * P) % MOD;
    for (int i = 1; i <= N; i++)
        hashes[i] = (hashes[i-1] * P + (s[i] - 'a' + 1)) % MOD;

    for (int len = 1; len <= N; len++) {
        mp.clear();
        for (int j = N-len+1; j >= 1; j--) {
            ll h = f(j, j + len - 1);
            while (mp[h].size() >= 2 && mp[h][1] > j + len - 1)
                mp[h].pop_front();

            to[j][len] = (mp[h].size() == 0 ? 0 : mp[h].front());
            if (to[j][len] <= j + len - 1)
                to[j][len] = 0;

            if (to[j][len])
                occ[j].push_back(len);
            mp[h].push_back(j);
        }
    }

    for (int i = 1; i <= N; i++) {
        for (int j = 1; j <= N; j++)
            dp[i][j] = 1e14;
    }

    for (int l = N; l >= 1; l--) {
        dp[l][l] = A;
        for (int r = l+1; r <= N; r++)
            dp[l][r] = min(dp[l][r], min(dp[l+1][r] + A, dp[l][r-1] + A));

        for (auto len : occ[l]) {
            int cnt = 1;
            int now = to[l][len];
            ll base = dp[l][l+len-1];
            while (now != 0) {
                int total = now - l - cnt * len;
                dp[l][now + len - 1] = min(dp[l][now + len - 1], total * A + B + C * (cnt + 1) + base);
                cnt++;
                now = to[now][len];
            }
        }

        for (int r = l+1; r <= N; r++)
            dp[l][r] = min(dp[l][r], min(dp[l+1][r] + A, dp[l][r-1] + A));
    }
    cout << dp[1][N] << "\n";
}
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