This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define all(v) v.begin(), v.end()
#define cmpr(x) lower_bound(all(crds), x) - crds.begin()
#pragma GCC optimize("Ofast")
#pragma GCC target("avx2")
class SegTree{
public:
vector<int> st;
vector<int> lz;
int len = 1;
SegTree(int n){
while(len < n) len *= 2;
st.resize(2 * len, INT_MAX);
for (int i = len; i < len + n; i++){
st[i] = 0;
}
for (int i = len - 1; i > 0; i--) {
st[i] = min(st[i * 2], st[i * 2 + 1]);
}
lz.resize(2 * len, 0);
}
void prop(int i){
st[i * 2] += lz[i];
st[i * 2 + 1] += lz[i];
lz[i * 2] += lz[i];
lz[i * 2 + 1] += lz[i];
lz[i] = 0;
}
void add(int f, int t, int v, int i, int s, int e){
if(f >= e || s >= t) return;
if(f <= s && e <= t){
st[i] += v;
lz[i] += v;
return;
}
prop(i);
add(f, t, v, i * 2, s, (s + e) / 2);
add(f, t, v, i * 2 + 1, (s + e) / 2, e);
st[i] = min(st[i * 2], st[i * 2 + 1]);
}
void add(int f, int t, int v) {
add(f, t, v, 1, 0, len);
}
};
bool can(int d, vector<array<int, 5>> v, int w, int h){
w -= d;
h -= d;
vector<int> crds;
for (auto &i : v) {
i[0] -= d;
i[1] -= d;
for (int j = 0; j < 4; j++) {
i[0] = max(0, i[0]);
i[1] = max(0, i[1]);
i[2] = min(w - 1, i[2]);
i[3] = min(h - 1, i[3]);
}
crds.push_back(i[0]);
crds.push_back(i[2]);
}
sort(all(crds));
crds.erase(unique(all(crds)), crds.end());
vector<vector<array<int, 3>>> ev(h + 1); //[y][i] -> t(0s, 1e), x, xx
SegTree st(crds.size() * 2 - 1);
for (auto &i : v) {
ev[i[1]].push_back({0, i[0], i[2]});
ev[i[3] + 1].push_back({1, i[0], i[2]});
}
int y = 0;
for (auto &es : ev) {
for (auto &e : es) {
auto& [t, x, xx] = e;
int cx = cmpr(x);
int cxx = cmpr(xx);
if(t == 0){
st.add(cx * 2, cxx * 2 + 1, 1);
}
else{
st.add(cx * 2, cxx * 2 + 1, -1);
}
}
if(st.st[1] == 0 && y != h) return true;
y++;
}
return false;
}
int main()
{
int w, h; cin >> w >> h;
int b; cin >> b;
if(b != 0) return 1;
int n; cin >> n;
vector<array<int, 5>> v(n);
for (auto &i : v){
cin >> i[0] >> i[1] >> i[2] >> i[3] >> i[4];
for (int j = 0; j < 4; j++)
i[j]--;
}
int l = -1, r = min(w, h), mid;
while(l < r){
mid = (l + r + 1) / 2;
if(can(mid, v, w, h)) l = mid;
else r = mid - 1;
}
cout << l + 1 << endl;
}
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