This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ari2 = array<int, 2>;
using ari3 = array<int, 3>;
using ari4 = array<int, 4>;
using arl2 = array<ll, 2>;
using arl3 = array<ll, 3>;
#define vt vector
#define all(x) begin(x), end(x)
#define size(x) (int((x).size()))
#define REP(a, b, c, d) for (int a = (b); (d) > 0 ? a <= (c) : a >= (c); a += (d))
#define FOR(a, b, c) REP(a, b, c, 1)
#define ROF(a, b, c) REP(a, b, c, -1)
void solve();
signed main() {
#ifndef DEBUG
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
#endif
int T = 1;
//cin >> T;
FOR(t, 1, T) {
solve();
}
}
void solve() {
int N, M, A, B;
cin >> N >> M >> A >> B;
int X[N], Y[N];
vt<int> vw, ve;
FOR(i, 0, N-1) {
cin >> X[i] >> Y[i];
if (X[i] == 0)
vw.push_back(i);
if (X[i] == A)
ve.push_back(i);
}
sort(all(vw), [&](const int &a, const int &b) {
return Y[a] < Y[b];
});
sort(all(ve), [&](const int &a, const int &b) {
return Y[a] < Y[b];
});
vt<vt<int>> adj(N), radj(N);
FOR(_, 1, M) {
int a, b, c;
cin >> a >> b >> c;
adj[--a].push_back(--b);
radj[b].push_back(a);
if (c == 2) {
adj[b].push_back(a);
radj[a].push_back(b);
}
}
{
queue<int> qu;
bool seen[N] = {};
for (int i : vw) {
seen[i] = true;
qu.push(i);
}
while (size(qu)) {
int i = qu.front();
qu.pop();
for (int j : adj[i])
if (!seen[j]) {
seen[j] = true;
qu.push(j);
}
}
vt<int> nve;
for (int i : ve)
if (seen[i])
nve.push_back(i);
ve = nve;
}
vt<int> L(N, -2e9), R(N, -2e9);
auto dijk = [&](vt<int> &V, vt<int> &sts, vt<vt<int>> &G, int mul) {
priority_queue<ari2> pq;
for (int i : sts) {
V[i] = Y[i] * mul;
pq.push({V[i], i});
}
while (size(pq)) {
auto [d, i] = pq.top();
pq.pop();
if (d < V[i])
continue;
for (int j : G[i])
if (d > V[j])
pq.push({V[j] = d, j});
}
};
dijk(L, ve, radj, -1);
dijk(R, ve, radj, 1);
int l = 0, r = 0;
vt<int> ans;
for (int i : vw) {
L[i] *= -1;
if (L[i] == 2e9)
ans.push_back(0);
else {
while (l < size(ve) && Y[ve[l]] < L[i])
l++;
while (r < size(ve) && Y[ve[r]] <= R[i])
r++;
ans.push_back(r - l);
}
}
reverse(all(ans));
for (int i : ans)
cout << i << '\n';
}
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