Submission #889439

#TimeUsernameProblemLanguageResultExecution timeMemory
889439ASN49KAliens (IOI16_aliens)C++14
60 / 100
2062 ms6236 KiB
#include <bits/stdc++.h>
#include "aliens.h"
using namespace std;
using i64=long long;
const i64 INF=1e18;
#define bug(x) cerr<<#x<<x<<'\n';
#define all(yy) yy.begin(),yy.end()
#define pb push_back
const int inf=1e9;
struct duo
{
    int l,r;
    bool operator <(const duo&b)const
    {
        if(l==b.l)
        {
            return r>b.r;
        }
        return l<b.l;
    }
};
////////////////////////////GEOMETRY
////////////////////////////////////
struct line
{
    i64 a,b;
    i64 calculate(int x)
    {
        return a*x+b;
    }
};
i64 intersect(const line& c,const line& d)
{
    return (d.b-c.b+c.a-d.a-1)/(c.a-d.a);
}
struct CHT
{
    deque<line>d;
    void add(const line e)
    {
        while(d.size()>=2 && intersect(d[d.size()-2],d.back())>=intersect(d.back(),e))
        {
            d.pop_back();
        }
        d.pb(e);
    }
    i64 query(int val)
    {
        while(d.size()>=2 && d[0].calculate(val)>=d[1].calculate(val))
        {
            d.pop_front();
        }
        return d[0].calculate(val);
    }
    void clear()
    {
        d.clear();
    }
};
i64 pow2(i64 x)
{
    return x*x;
}
/////////////////////////////////////////////////////
/////////////////////////////////////////////////////
i64 take_photos(int n, int m, int k, vector<int> rr, vector<int> cc)
{
    vector<duo>a(n);
    for(int i=0;i<n;i++)
    {
        a[i]={min(rr[i],cc[i]),max(rr[i],cc[i])};
    }
    vector<duo>aux=a;
    a.clear();
    sort(all(aux));
    int maxx=-1;
    for(auto &c:aux)
    {
        if(c.r>maxx)
        {
            a.pb(c);
            maxx=c.r;
        }
    }
    aux.clear();
    n=(int)a.size();
    vector<i64>dp(n+1,INF);
    for(int _=0;_<k;_++)
    {
        CHT cht;
        cht.add({-2*(a[0].l-1),pow2(a[0].l-1)});
        for(int i=0;i<n;i++)
        {
            i64 sol=pow2(a[i].r)+cht.query(a[i].r);
            if(i!=n-1)
            {
                cht.add({-2*(a[i+1].l-1) , pow2(a[i+1].l-1)-pow2(max(0,a[i].r-a[i+1].l+1))+dp[i]});
            }
            dp[i]=sol;
        }
    }
    return dp[n-1];
}
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