Submission #889304

#TimeUsernameProblemLanguageResultExecution timeMemory
889304hafoCoin Collecting (JOI19_ho_t4)C++14
100 / 100
40 ms7532 KiB
#include <bits/stdc++.h> #define ll long long #define ull unsigned ll #define pb push_back #define pa pair<int, int> #define pall pair<ll, int> #define fi first #define se second #define TASK "test" #define Size(x) (int) x.size() #define all(x) x.begin(), x.end() using namespace std; template<typename T1, typename T2> bool mini (T1 &a, T2 b) {if(a > b) a = b; else return 0; return 1;} template<typename T1, typename T2> bool maxi (T1 &a, T2 b) {if(a < b) a = b; else return 0; return 1;} const int MOD = 1e9 + 7; const int LOG = 20; const int maxn = 2e5 + 7; const ll oo = 1e18 + 69; int n; pa a[maxn]; struct sub2 { static const int maxn = 2e3 + 7; ll dp[maxn][maxn]; void solve() { sort(a + 1, a + 1 + n); for(int i = 1; i <= n; i++) cout<<a[i].fi<<" "<<a[i].se<<"\n"; for(int i = 0; i <= n; i++) { for(int j = 0; j <= n; j++) dp[i][j] = oo; } dp[0][0] = 0; for(int i = 1; i <= n; i++) { for(int j = 0; j <= min(i, n / 2); j++) { int rem = i - j; if(rem > n / 2) continue; if(j > 0) { mini(dp[i][j], dp[i - 1][j - 1] + abs(a[i].fi - j) + abs(a[i].se - 1)); } if(rem > 0) { mini(dp[i][j], dp[i - 1][j] + abs(a[i].fi - rem) + abs(a[i].se - 2)); } } } cout<<dp[n][n / 2]; } } sub2; struct sub3 { int cnt[maxn][2], d[2]; void solve() { ll ans = 0; for(int i = 1; i <= n; i++) { int x = a[i].fi, y = a[i].se; if(x < 1) { ans += 1 - x; x = 1; } if(x > n / 2) { ans += x - n / 2; x = n / 2; } if(y < 1) { ans += 1 - y; y = 1; } if(y > 2) { ans += y - 2; y = 2; } cnt[x][y - 1]++; } for(int i = 1; i <= n / 2; i++) { for(int j = 0; j < 2; j++) d[j] += cnt[i][j] - 1; for(int j = 0; j < 2; j++) { if(d[j] > 0 && d[j ^ 1] < 0) { int t = min(d[j], - d[j ^ 1]); ans += t; d[j] -= t; d[j ^ 1] += t; } } for(int j = 0; j < 2; j++) ans += abs(d[j]); } cout<<ans; } } sub3; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); //freopen(TASK".inp", "r", stdin); //freopen(TASK".out", "w", stdout); cin>>n; n *= 2; for(int i = 1; i <= n; i++) cin>>a[i].fi>>a[i].se; // sub2.solve(); sub3.solve(); return 0; }
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