Submission #888575

#TimeUsernameProblemLanguageResultExecution timeMemory
888575JakobZorzHoliday (IOI14_holiday)C++17
0 / 100
5060 ms2392 KiB
#include"holiday.h" #include<iostream> #include<vector> #include<algorithm> using namespace std; typedef long long ll; // if you can only walk in one direction // return a[d] = most score if you have d days vector<ll>get3(vector<int>arr){ vector<ll>res; for(int d=0;d<=2*(int)arr.size();d++){ // r = how far you go ll res1=0; for(int r=0;r<=d&&r<=(int)arr.size();r++){ // c = how many cities you actually visit int c=d-r; vector<ll>vals; for(int i=0;i<r;i++){ vals.push_back(arr[i]); } sort(vals.begin(),vals.end()); reverse(vals.begin(),vals.end()); ll res2=0; for(int i=0;i<c&&i<(int)vals.size();i++) res2+=vals[i]; res1=max(res1,res2); } res.push_back(res1); } return res; } // if you can only walk in one direction and have to go back // return a[d] = most score if you have d days vector<ll>get2(vector<int>arr){ vector<ll>res; for(int d=0;d<=3*(int)arr.size();d++){ // r = how far you go ll res1=0; for(int r=0;2*(r-1)<=d&&r<=(int)arr.size();r++){ // c = how many cities you actually visit int c=d-2*(r-1); vector<ll>vals; for(int i=0;i<r;i++){ vals.push_back(arr[i]); } sort(vals.begin(),vals.end()); reverse(vals.begin(),vals.end()); ll res2=0; for(int i=0;i<c&&i<(int)vals.size();i++) res2+=vals[i]; res1=max(res1,res2); } res.push_back(res1); } return res; } // if you first start walking to the left and then right ll get1(vector<int>arr,int d,int s){ int n=(int)arr.size(); vector<int>arr1,arr2; for(int i=s;i>=0;i--) arr1.push_back(arr[i]); for(int i=s+1;i<n;i++) arr2.push_back(arr[i]); vector<ll>val1=get2(arr1),val2=get3(arr2); /*cout<<"val1 "; for(ll i:val1) cout<<i<<" "; cout<<"\n"; cout<<"val2 "; for(ll i:val2) cout<<i<<" "; cout<<"\n";*/ ll res=0; for(int d1=0;d1<=d;d1++){ int d2=d-d1; if(d1<(int)val1.size()&&d2<(int)val2.size()){ res=max(res,val1[d1]+val2[d2]); } } return res; } ll findMaxAttraction(int n,int start,int d,int attraction[]){ vector<int>arr; for(int i=0;i<n;i++) arr.push_back(attraction[i]); ll res=get1(arr,d,start); reverse(arr.begin(),arr.end()); return max(res,get1(arr,d,n-start-1)); }
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