Submission #88807

#	Time	Username	Problem	Language	Result	Execution time	Memory
88807		jasony123123	Kas (COCI17_kas)	C++11	90 / 100	2089 ms	418340 KiB

kas

#define _CRT_SECURE_NO_WARNINGS
#include <bits/stdc++.h>
#include <unordered_map>
//#include <ext/pb_ds/tree_policy.hpp>
//#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
//using namespace __gnu_pbds;
#define FOR(i,start,end) for(int i=start;i<(int)(end);i++)
#define FORE(i,start,end) for(int i=start;i<=(int)end;i++)
#define RFOR(i,start,end) for(int i = start; i>end; i--)
#define RFORE(i,start,end) for(int i = start; i>=end; i--)
#define all(a) a.begin(), a.end()
#define mt make_tuple
#define v vector
#define sf scanf
#define pf printf
#define dvar(x) cout << #x << " := " << x << "\n"
#define darr(x,n) FOR(i,0,n) cout << #x << "[" << i << "]" << " := " << x[i] << "\n"
typedef long long ll;
typedef long double ld;
typedef pair<int, int > pii;
typedef pair<ll, ll> pll;
const ll MOD = 1000000007LL;
const ll PRIME = 105943LL;
const ll INF = 1e18;
//template <class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<class T> void minn(T &a, T b) { a = min(a, b); }
template<class T> void maxx(T &a, T b) { a = max(a, b); }
void io() {
#ifdef LOCAL_PROJECT 
	freopen("input.in", "r", stdin); freopen("output.out", "w", stdout);
#else 
	/* online submission */
#endif 
	ios_base::sync_with_stdio(false); cin.tie(NULL);
}
/**************************COCI 2016-2017 R4 P3 *************************/

int N;
int A[501];
unordered_map<int, int> alldp[501];

inline void add(unordered_map<int, int> &dp, int key, int val) {
	key = abs(key);
	auto it = dp.find(key);
	if (it == dp.end()) {
		dp[key] = val;
	}
	else {
		minn(it->second, val);
	}
}

int main() {
	io();
	int sum = 0;
	cin >> N;
	FORE(i, 1, N) {
		cin >> A[i];
		sum += A[i];
	}
	alldp[0][0] = 0;
	FORE(i, 1, N) {
		for (pii old : alldp[i-1]) {
			add(alldp[i], old.first + A[i], old.second);
			add(alldp[i], old.first - A[i], old.second);
			add(alldp[i], old.first, old.second + A[i]);
		}
	}
	int leftover = alldp[N][0];
	int ans = sum - leftover;
//	assert(ans % 2 == 0);
	ans /= 2;
	ans += leftover;
	cout << ans << "\n";
	return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 10 / 10
• Subtask 6: 10 / 10
• Subtask 7: 10 / 10
• Subtask 8: 10 / 10
• Subtask 9: 10 / 10
• Subtask 10: 0 / 10