Submission #887734

#	Time	Username	Problem	Language	Result	Execution time	Memory
887734		hamidh100	Land of the Rainbow Gold (APIO17_rainbow)	C++17	0 / 100	3 ms	348 KiB

rainbow

#include "rainbow.h"
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair<int, int> PII;
typedef pair<ll, ll> PLL;
typedef vector<int> VI;
typedef vector<ll> VL;
#define PB push_back
#define MP make_pair
#define all(a) (a).begin(), (a).end()
#define endl '\n'
#define dbg(x) cerr << '[' << #x << ": " << x << "]\n"
#define dbg2(x, y) cerr << '[' << #x << ": " << x << ", " << #y << ": " << y << "]\n"
#define YES cout << "YES\n"
#define NO cout << "NO\n"

const ll INF = (ll)2e18 + 1386;
const ld EPS = 0.000000000000001;
const int MOD = 1e9 + 7;

inline int _add(int a, int b){ int res = a + b; return (res >= MOD ? res - MOD : res); }
inline int _neg(int a, int b){ int res = (abs(a - b) < MOD ? a - b : (a - b) % MOD); return (res < 0 ? res + MOD : res); }
inline int _mlt(ll a, ll b){ return (a * b % MOD); }
inline void fileIO(string i, string o){ freopen(i.c_str(), "r", stdin); freopen(o.c_str(), "w", stdout); }

const int MAXN = 51;

int par[MAXN * MAXN], n, m;
int a[MAXN][MAXN];

inline int c(int x, int y){ return (x - 1) * m + y; }

int getpar(int v){
    return par[v] == v ? v : par[v] = getpar(par[v]);
}

void merge(int u, int v){
    u = getpar(u), v = getpar(v);
    par[u] = v;
}

void init(int R, int C, int sr, int sc, int M, char *S) {
    n = R, m = C;
    iota(par, par + R * C + 1, 0);
    a[sr][sc] = 1;
    for (int i = 0; i < M; i++){
        char ch = S[i];
        if (ch == 'N') a[--sr][sc] = 1;
        else if (ch == 'S') a[++sr][sc] = 1;
        else if (ch == 'E') a[sr][++sc] = 1;
        else a[sr][--sc] = 1;
    }
    for (int i = 1; i <= R; i++){
        for (int j = 1; j <= C; j++){
            cout << a[i][j];
        }
        cout << endl;
    }
    cout << endl;
}

int dx[] = {0, 0, +1, -1};
int dy[] = {+1, -1, 0, 0};

int colour(int ar, int ac, int br, int bc) {
    for (int i = ar; i <= br; i++){
        for (int j = ac; j <= bc; j++){
            if (a[i][j] == 1) continue;
            for (int ii = 0; ii < 4; ii++){
                int x = i + dx[ii], y = j + dy[ii];
                if (x >= ar && x <= br && y >= ac && y <= bc && a[x][y] == 0){
                    merge(c(i, j), c(x, y));
                }
            }
        }
    }
    set<int> st;
    for (int i = ar; i <= br; i++){
        for (int j = ac; j <= bc; j++){
            if (a[i][j] == 0) st.insert(getpar(c(i, j)));
        }
    }
    for (int i = ar; i <= br; i++){
        for (int j = ac; j <= bc; j++){
            par[c(i, j)] = c(i, j);
        }
    }
    return (int)st.size();
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 12
• Subtask 3: 0 / 24
• Subtask 4: 0 / 27
• Subtask 5: 0 / 26