This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <cmath>
#include <iomanip>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <fstream>
#include <bitset>
typedef long long ll;
using namespace std;
const int N = 1e6 + 10;
int sz = 0;
struct Node {
int left;
int right;
int mx;
};
int a[N], l[N];
int b[N];
int root[N];
Node tree[30 * N];
void build_tree(int v, int tl, int tr) {
tree[v].left = 0;
tree[v].right = 0;
tree[v].mx = 0;
if (tl != tr) {
tree[v].left = ++sz;
tree[v].right = ++sz;
int tm = (tl + tr) / 2;
build_tree(tree[v].left, tl, tm);
build_tree(tree[v].right, tm + 1, tr);
}
}
void update(int v, int prev_v, int tl, int tr, int pos, int val) {
if (tl == tr) {
tree[v].mx = val;
return;
}
int tm = (tl + tr) / 2;
if (pos <= tm) {
tree[v].right = tree[prev_v].right;
tree[v].left = ++sz;
update(tree[v].left, tree[prev_v].left, tl, tm, pos, val);
}
else {
tree[v].left = tree[prev_v].left;
tree[v].right = ++sz;
update(tree[v].right, tree[prev_v].right, tm + 1, tr, pos, val);
}
tree[v].mx = max(tree[tree[v].left].mx, tree[tree[v].right].mx);
}
int MAX(int v, int tl, int tr, int l, int r) {
if (tl > r || tr < l) return 0;
if (tl >= l && tr <= r) return tree[v].mx;
int tm = (tl + tr) / 2;
return max(MAX(tree[v].left, tl, tm, l, r), MAX(tree[v].right, tm + 1, tr, l, r));
}
int main() {
int n, q;
cin >> n >> q;
for (int i = 1; i <= 24 * n; i++) {
tree[i] = { 0, 0, 0 };
}
a[0] = 1e9 + 10;
vector <pair<int, int>> updates;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
for (int i = 1; i <= n; i++) {
l[i] = i - 1;
while (a[i] >= a[l[i]]) {
l[i] = l[l[i]];
}
b[i] = a[i] + a[l[i]];
updates.push_back({ l[i], i });
}
updates.push_back({ n, 0 });
sort(updates.begin(), updates.end());
root[n] = ++sz;
build_tree(root[n], 1, n);
for (int i = n - 1; i >= 0; i--) {
root[i] = ++sz;
update(root[i], root[i + 1], 1, n, updates[i].second, b[updates[i].second]);
}
while (q--) {
int l, r, k;
cin >> l >> r >> k;
int ind = lower_bound(updates.begin(), updates.end(), make_pair(l, 0)) - updates.begin();
if (MAX(root[ind], 1, n, l, r) <= k) cout << 1 << "\n";
else cout << 0 << "\n";
}
}
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