Submission #886178

#	Time	Username	Problem	Language	Result	Execution time	Memory
886178		nnhzzz	Sum Zero (RMI20_sumzero)	C++14	61 / 100	262 ms	20816 KiB

sumzero

/* [Author: Nguyen Ngoc Hung] - From THPT Ngo Gia Tu with Love */

#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx2,fma,bmi,bmi2,sse4.2,popcnt,lzcnt")

#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <exception>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iosfwd>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <locale>
#include <map>
#include <new>
#include <numeric>
#include <ostream>
#include <queue>
#include <set>
#include <unordered_set>
#include <sstream>
#include <stack>
#include <stdexcept>
#include <streambuf>
#include <string>
#include <utility>
#include <valarray>
#include <vector>
#include <cstring>
#include <unordered_map>
#include <cmath>
#include <array>
#include <cassert>
#include <random>
#include <chrono>

using namespace std;

#define        __nnhzzz__  signed main()
#define          BIT(i,j)  ((i>>j)&1LL)
#define           MASK(i)  (1LL<<(i))
#define            ALL(x)  (x).begin(),(x).end()
#define             SZ(x)  (int)(x).size()
#define               _PB  push_back
#define                fi  first
#define                se  second
#define                ll  long long
#define                ld  long double
#define                vi  vector<int>
#define               vvi  vector<vi>
#define              vvvi  vector<vvi>
#define               pii  pair<int,int>
#define              vpii  vector<pii>
#define             vvpii  vector<vpii>
#define REPDIS(i,be,en,j)  for(int i = (be); i<=(en); i+=j)
#define     REPD(i,be,en)  for(int i = (be); i>=(en); i--)
#define      REP(i,be,en)  for(int i = (be); i<=(en); i++)
#define              endl  "\n"
#define                MP  make_pair
// #define               int  ll


//-----------------------------------------------------------------------------------------------//
int readInt(){
    char c;
    do{ c = getchar(); }while(c!='-' && !isdigit(c));
    bool neg = (c=='-');
    int res = neg?0:c-'0';
    while(isdigit(c=getchar())) res = (res<<3)+(res<<1)+(c-'0');
    return neg?-res:res;
}
//------------------------------------------------------------------------------------------------//
const  ll   LINF = 1e18;
const int    INF = 1e9;
const int    LOG = 4;
const int   MAXN = 4e5+7;
const int      N = 1e2+3;
const int    MOD = 1e9+7;
const int   BASE = 5;
const  ld    EPS = 1e-9;
const  ld     PI = acos(-1);
const int OFFSET = 1e3;
//------------------------------------------------------------------------------------------------//
template<typename T1, typename T2> bool mini(T1 &a, T2 b){if(a>b){a=b;return true;}return false;}
template<typename T1, typename T2> bool maxi(T1 &a, T2 b){if(a<b){a=b;return true;}return false;}
template<typename T> T gcd(T a, T b) { while(b) { a %= b; swap(a,b); } return a; }
template<typename T> T lcm(T a, T b) { return a/gcd(a,b)*b; }
//------------------------------------------------------------------------------------------------//

/*
----------------------------------------------------------------
    END OF TEMPLATE
----------------------------------------------------------------
    Nguyen Ngoc Hung - nnhzzz
    Training for VOI24 gold medal
----------------------------------------------------------------
*/

int a[MAXN];
int n,query;

// namespace sub1{
//     void solve(){
//         REP(t,1,query){
//             int l = q[t].fi,r = q[t].se;
//             set<int> s; s.insert(0);
//             int sum = 0,res = 0;
//             REP(i,l,r){
//                 sum += a[i];
//                 if(s.find(sum)!=s.end()){
//                     s.clear();
//                     s.insert(0);
//                     sum = 0;
//                     ++res;
//                 }else{
//                     s.insert(sum);
//                 }
//             }
//             cout << res << endl;
//         }
//     }
// }

// namespace sub2{
//     int f[MAXN][LOG];

//     void solve(){
//         map<int,int> mp;
//         int sum = 0;
//         REP(i,1,n) sum += a[i];
//         f[n+1][0] = n+1;
//         int MIN = n+1;
//         REPD(i,n,0){
//             if(mp.count(sum)) mini(MIN,mp[sum]);
//             f[i][0] = MIN;
//             mp[sum] = i;
//             sum -= a[i];
//         }
//         REP(j,1,LOG-1){
//             REP(i,0,n+1){
//                 f[i][j] = f[i][j-1];
//                 REP(k,1,MASK(BASE)-1){
//                     f[i][j] = f[f[i][j]][j-1];
//                 }
//             }
//         }
//         REP(t,1,query){
//             int l = q[t].fi-1,r = q[t].se,res = 0;
//             REPD(i,LOG-1,0){
//                 while(f[l][i]<=r){
//                     res += MASK(i*BASE);
//                     l = f[l][i];
//                 }
//             }
//             cout << res << endl;
//         }
//     }
// }

namespace sub3{
    int nxt[MAXN],jump[MAXN],lvl[MAXN];

    void solve(){
        map<ll,int> mp;
        ll sum = 0;
        REP(i,1,n) sum += a[i];
        jump[n+1] = nxt[n+1] = n+1;
        int MIN = n+1;
        REPD(i,n,0){
            if(mp.count(sum)) mini(MIN,mp[sum]);
            nxt[i] = MIN;
            mp[sum] = i;
            sum -= a[i];
        }
        mp.clear();
        lvl[n+1] = 0;
        REPD(i,n,0){
            int x = nxt[i];
            if(lvl[x]==lvl[jump[x]]){
                lvl[i] = lvl[x]+1;
                jump[i] = jump[jump[x]];
            }else{
                lvl[i] = 1;
                jump[i] = nxt[i];
            }
        }
        REP(t,1,query){
            // int l = q[t].fi-1,r = q[t].se,res = 0;
            int res = 0,l,r; cin >> l >> r; --l;
            while(nxt[l]<=r){
                if(jump[l]<=r){
                    res += MASK(lvl[l])-1;
                    l = jump[l];
                }else{
                    ++res;
                    l = nxt[l];
                }
            }
            cout << res << endl;
        }
    }
}

void solve(){
    cin >> n;
    REP(i,1,n) cin >> a[i];
    cin >> query;
    // REP(t,1,query) cin >> q[t].fi >> q[t].se;
    sub3::solve(); return ;
    // if(n<=5000 && query<=5000){
    //     sub1::solve();
    //     return ;
    // }
    // if(n<=100000 && query<=100000){
    //     sub2::solve();
    //     return ;
    // }
    sub3::solve();
}

__nnhzzz__{
    ios::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    #define task "test"
    if(fopen(task".inp","r")){
        freopen(task".inp","r",stdin);
        freopen(task".out","w",stdout);
    }
    #define task1 "nnhzzz"
    if(fopen(task1".inp","r")){
        freopen(task1".inp","r",stdin);
        freopen(task1".out","w",stdout);
    }

    int test = 1;

    while(test--){
      solve();
    }
    cerr << "\nTime elapsed: " << 1000*clock()/CLOCKS_PER_SEC << "ms\n";
    return 0;
}

/**  /\_/\
 *  (= ._.)
 *  / >TL \>AC
**/

Compilation message (stderr)

sumzero.cpp: In function 'int main()':
sumzero.cpp:233:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  233 |         freopen(task".inp","r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
sumzero.cpp:234:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  234 |         freopen(task".out","w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
sumzero.cpp:238:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  238 |         freopen(task1".inp","r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
sumzero.cpp:239:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  239 |         freopen(task1".out","w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 22 / 22
• Subtask 2: 39 / 39
• Subtask 3: 0 / 39