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Submission #88226

# Submission time Handle Problem Language Result Execution time Memory
88226 2018-12-04T15:48:47 Z kjain_1810 Maja (COCI18_maja) C++11
110 / 110
 233 ms 1088 KB 
#include <bits/stdc++.h>
#define pb push_back
#define f first
#define s second
#define ind(a) scanf("%d", &a)
#define inlld(a) scanf("%lld", &a)
#define ind2(a, b) scanf("%d%d", &a, &b)
#define inlld2(a, b) scanf("%lld%lld", &a, &b)
#define ind3(a, b, c) scanf("%d%d%d", &a, &b, &c)
#define inlld3(a, b, c) scanf("%lld%lld%lld", &a, &b, &c)

using namespace std;

const int N=105+5;
const int MOD=1e9+7;

typedef long long ll;
typedef long double ld;

ll n, m, stx, sty, k, dp[2][N][N], arr[N][N];

int main()
{
    inlld2(n, m);
    inlld2(stx, sty);
    inlld(k);
    for(ll a=1; a<=n; a++)
        for(ll b=1; b<=m; b++)
        {
            inlld(arr[a][b]);
            for(ll c=0; c<=n+m; c++)
                dp[c][a][b]=-1e18;
        }
    dp[0][stx][sty]=0;
    for(ll steps=1; steps<=min(k/2, n*m-1); steps++)
        for(ll a=1; a<=n; a++)
            for(ll b=1; b<=m; b++)
            {
                if(a>1)
                    dp[steps%2][a][b]=max(dp[steps%2][a][b], dp[(steps-1)%2][a-1][b]+arr[a][b]);
                if(b>1)
                    dp[steps%2][a][b]=max(dp[steps%2][a][b], dp[(steps-1)%2][a][b-1]+arr[a][b]);
                if(a<n)
                    dp[steps%2][a][b]=max(dp[steps%2][a][b], dp[(steps-1)%2][a+1][b]+arr[a][b]);
                if(b<m)
                    dp[steps%2][a][b]=max(dp[steps%2][a][b], dp[(steps-1)%2][a][b+1]+arr[a][b]);
                // printf("%lld %lld %lld %lld\n", steps, a, b, dp[steps][a][b]);
            }
    if(k/2<=n*m-1)
    {
        ll ans=0;
        for(ll a=1; a<=n; a++)
            for(ll b=1; b<=m; b++)
                ans=max(ans, 2*dp[(k/2)%2][a][b]-arr[a][b]);
        printf("%lld\n", ans);
        return 0;
    }
    ll ans=0;
    for(ll a=1; a<=n; a++)
        for(ll b=1; b<=m; b++)
        {
            ll here=dp[(n*m-1)%2][a][b];
            ll toadd=0;
            if(a>1)
                toadd=max(toadd, arr[a-1][b]);
            if(a<n)
                toadd=max(toadd, arr[a+1][b]);
            if(b<m)
                toadd=max(toadd, arr[a][b+1]);
            if(b>1)
                toadd=max(toadd, arr[a][b-1]);
            ans=max(ans, 2*here+((k-2*n*m+2)*(toadd+arr[a][b]))/2-arr[a][b]);
        }
    printf("%lld\n", ans);
}

Compilation message

maja.cpp: In function 'int main()':
maja.cpp:8:27: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define inlld2(a, b) scanf("%lld%lld", &a, &b)
                      ~~~~~^~~~~~~~~~~~~~~~~~~~
maja.cpp:24:5: note: in expansion of macro 'inlld2'
     inlld2(n, m);
     ^~~~~~
maja.cpp:8:27: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define inlld2(a, b) scanf("%lld%lld", &a, &b)
                      ~~~~~^~~~~~~~~~~~~~~~~~~~
maja.cpp:25:5: note: in expansion of macro 'inlld2'
     inlld2(stx, sty);
     ^~~~~~
maja.cpp:6:23: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define inlld(a) scanf("%lld", &a)
                  ~~~~~^~~~~~~~~~~~
maja.cpp:26:5: note: in expansion of macro 'inlld'
     inlld(k);
     ^~~~~
maja.cpp:6:23: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define inlld(a) scanf("%lld", &a)
                  ~~~~~^~~~~~~~~~~~
maja.cpp:30:13: note: in expansion of macro 'inlld'
             inlld(arr[a][b]);
             ^~~~~

Subtask #1
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct

Subtask #2
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 3 ms 392 KB Output is correct
2 Correct 1 ms 436 KB Output is correct

Subtask #3
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 2 ms 504 KB Output is correct
2 Correct 3 ms 632 KB Output is correct

Subtask #4
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 3 ms 632 KB Output is correct
2 Correct 2 ms 632 KB Output is correct

Subtask #5
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 22 ms 632 KB Output is correct
2 Correct 2 ms 632 KB Output is correct
3 Correct 231 ms 920 KB Output is correct

Subtask #6
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 3 ms 920 KB Output is correct
2 Correct 143 ms 1052 KB Output is correct
3 Correct 233 ms 1052 KB Output is correct

Subtask #7
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 114 ms 1052 KB Output is correct
2 Correct 201 ms 1088 KB Output is correct

Subtask #8
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 17 ms 1088 KB Output is correct
2 Correct 17 ms 1088 KB Output is correct

Subtask #9
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 4 ms 1088 KB Output is correct
2 Correct 3 ms 1088 KB Output is correct

Subtask #10
11.0 / 11.0

# Verdict Execution time Memory Grader output
1 Correct 14 ms 1088 KB Output is correct
2 Correct 3 ms 1088 KB Output is correct