Submission #882007

#TimeUsernameProblemLanguageResultExecution timeMemory
882007_callmelucianBuilding Bridges (CEOI17_building)C++14
0 / 100
1 ms604 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int,int> pii; #define all(v) v.begin(), v.end() struct line { ll slope, c; line (ll u = 0, ll v = 0) : slope(u), c(v) {} ll calc (ll x) {return slope * x + c;} }; struct liChao { vector<line> tr; liChao (int sz) : tr(4 * sz, line(0, LLONG_MAX)) {} void update (int k, line seg, int l, int r) { if (l + 1 == r) { if (seg.calc(l) < tr[k].calc(l)) tr[k] = seg; return; } int mid = (l + r) / 2; if (seg.slope > tr[k].slope) swap(seg, tr[k]); // seg must have lower slope if (seg.calc(mid) < tr[k].calc(mid)) { update(2 * k, tr[k], l, mid); tr[k] = seg; } else update(2 * k + 1, seg, mid, r); } ll query (int pos, int k, int l, int r) { if (l + 1 == r) return tr[k].calc(pos); int mid = (l + r) / 2; if (pos < mid) return min(tr[k].calc(pos), query(pos, 2 * k, l, mid)); return min(tr[k].calc(pos), query(pos, 2 * k + 1, mid, r)); } }; const int M = 9; ll dp[M], h[M], w[M]; ll f1 (int k) { return -2 * h[k]; } ll f2 (int k) { return dp[k] + h[k] * h[k] - w[k]; } ll f3 (int k) { return h[k] * h[k] + w[k - 1]; } int main() { ios::sync_with_stdio(0); cin.tie(0); int n; cin >> n; for (int i = 1; i <= n; i++) cin >> h[i]; for (int i = 1; i <= n; i++) { cin >> w[i]; w[i] += w[i - 1]; } liChao tree(M); tree.update(1, line(f1(1), f2(1)), 0, M); for (int i = 2; i <= n; i++) { dp[i] = tree.query(h[i], 1, 0, M) + f3(i); tree.update(1, line(f1(i), f2(i)), 0, M); } cout << dp[n]; return 0; }
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