Submission #880572

#	Time	Username	Problem	Language	Result	Execution time	Memory
880572		khoquennguoiminhthuong	Holiday (IOI14_holiday)	C++14	100 / 100	200 ms	48212 KiB

holiday

#include <bits/stdc++.h>

using namespace std;
int n;
int a[100005];
int pos;
int d;
long long ans=0;
struct node
{
int idl,idr,cnt;
long long sum;
}tree[2000005];
int goc[100005];
int timee;
vector<long long>vec;
void update(int nxt,int pre,int l,int r,int i,int val)
{
if(l>i||r<i||l>r)return ;
if(l==r)
{
tree[nxt].sum=tree[pre].sum+val*vec[l-1];
tree[nxt].cnt=tree[pre].cnt+val;
return;
}
int mid=(l+r)/2;
if(i<=mid)
{
tree[nxt].idr=tree[pre].idr;
tree[nxt].idl=++timee;
update(tree[nxt].idl,tree[pre].idl,l,mid,i,val);
}
else
{
tree[nxt].idl=tree[pre].idl;
tree[nxt].idr=++timee;
update(tree[nxt].idr,tree[pre].idr,mid+1,r,i,val);
}
tree[nxt].cnt=tree[tree[nxt].idl].cnt+tree[tree[nxt].idr].cnt;
tree[nxt].sum=tree[tree[nxt].idl].sum+tree[tree[nxt].idr].sum;
//cout<<nxt<<" "<<tree[nxt].sum<<'\n';
}
long long getsum(int nxt,int pre,int l,int r,int cnt)
{
if(cnt<=0)return 0;
if(l==r)return 1LL*cnt*vec[l-1];
int mid=(l+r)/2;
int vv=tree[tree[nxt].idr].cnt-tree[tree[pre].idr].cnt;
if(vv>=cnt)return getsum(tree[nxt].idr,tree[pre].idr,mid+1,r,cnt);
else return tree[tree[nxt].idr].sum-tree[tree[pre].idr].sum+getsum(tree[nxt].idl,tree[pre].idl,l,mid,cnt-vv);
}
void calc(int l,int r,int liml,int limr)
{
if(l>r)return ;
int mid=(l+r)/2;
long long val=-1;
long long vt=liml;
for(int i=liml;i<=limr;i++)
{
int ll=pos-mid;
int rr=i-pos;
int cnt=d-(ll+rr)-min(ll,rr);
cnt=min(cnt,i-mid+1);
if(cnt<0)continue;
long long sum=getsum(goc[i],goc[mid-1],1,n,cnt);
if(sum>val)
{val=sum;vt=i;}
}
ans=max(ans,val);
calc(l,mid-1,liml,vt);
calc(mid+1,r,vt,limr);
}
long long findMaxAttraction(int _n,int _start,int _m,int _a[])
{
n=_n;
pos=_start;
pos++;
d=_m;
for(int i=1;i<=n;i++)a[i]=_a[i-1];
for(int i=1;i<=n;i++)vec.push_back(a[i]);
sort(vec.begin(),vec.end());
vec.erase(unique(vec.begin(),vec.end()),vec.end());
for(int i=1;i<=n;i++)a[i]=lower_bound(vec.begin(),vec.end(),a[i])-vec.begin()+1;
for(int i=1;i<=n;i++)
{
goc[i]=++timee;
update(goc[i],goc[i-1],1,n,a[i],1);
}
calc(1,pos,pos,n);
return ans;
}

• Subtask 1: 7 / 7
• Subtask 2: 23 / 23
• Subtask 3: 17 / 17
• Subtask 4: 53 / 53