Submission #879767

#TimeUsernameProblemLanguageResultExecution timeMemory
879767TAhmed33Papričice (COCI20_papricice)C++98
15 / 110
12 ms36188 KiB
#include <bits/stdc++.h> using namespace std; const int MAXN = 2e5 + 25; #define mid ((l + r) >> 1) #define tl (node + 1) #define tr (node + 2 * (mid - l + 1)) const int bad = -1e9; int comb (int a, int b, int c) { return abs(2 * a - c) < abs(2 * b - c) ? a : b; } struct SegmentTree { set <int> tree[2 * MAXN]; int arr[MAXN]; void build (int l, int r, int node) { for (int i = l; i <= r; i++) tree[node].insert(arr[i]); if (l == r) return; build(l, mid, tl); build(mid + 1, r, tr); } int get (int l, int r, int a, int b, int c, int node) { if (a > b || l > r) return bad; if (l > b || r < a) return bad; if (l >= a && r <= b) { int ret = bad; auto t = tree[node].lower_bound(c); if (t != tree[node].end()) ret = comb(ret, *t, c); if (t != tree[node].begin()) { t--; ret = comb(ret, *t, c); } return ret; } return comb(get(l, mid, a, b, c, tl), get(mid + 1, r, a, b, c, tr), c); } } cur; vector <int> adj[MAXN]; int sze[MAXN], n, in[MAXN], out[MAXN], t; set <int> dd[MAXN]; typedef long long ll; int mn = 1e9; void dfs (int pos, int par) { sze[pos] = 1; in[pos] = ++t; int mx = bad; for (auto j : adj[pos]) { if (j == par) continue; dfs(j, pos); sze[pos] += sze[j]; if (dd[pos].size() < dd[j].size()) swap(dd[pos], dd[j]); for (auto i : dd[j]) dd[pos].insert(i); dd[j].clear(); } dd[pos].insert(sze[pos]); for (auto i : dd[pos]) { if (abs(2 * i - sze[pos]) < abs(2 * mx - sze[pos])) { mx = i; } } if (sze[pos] != 1 && pos != 1) mn = min(mn, max({n - sze[pos], sze[pos] - mx, mx}) - min({n - sze[pos], sze[pos] - mx, mx})); out[pos] = t; } bool check (int x, int y) { return in[y] < in[x] && in[x] <= out[y]; } int main () { cin >> n; for (int i = 1; i < n; i++) { int a, b; cin >> a >> b; adj[a].push_back(b); adj[b].push_back(a); } dfs(1, -1); for (int i = 2; i <= n; i++) { cur.arr[in[i]] = sze[i]; } cur.build(2, n, 1); for (int i = 2; i <= n; i++) { int x = comb(cur.get(2, n, 2, in[i] - 1, n - sze[i], 1), cur.get(2, n, out[i] + 1, n, n - sze[i], 1), n - sze[i]); mn = min(mn, max({sze[i], x, n - x - sze[i]}) - min({sze[i], x, n - sze[i] - x})); } cout << mn << '\n'; }
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