Submission #879732

#	Time	Username	Problem	Language	Result	Execution time	Memory
879732		binh192004	Preokret (COCI18_preokret)	C++17	50 / 50	1 ms	604 KiB

preokret

#include <bits/stdc++.h>

using namespace std;

typedef long double ld;
mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count());
#define int long long
#define double long double
#define all(x) (x).begin(), (x).end()
#define pii pair<int, int>
#define lowbit(x) x & (-x);
#define inf 1e18
#define _inf -1e18
#define pyes cout << "YES" << endl
#define pno cout << "NO" << endl
#define inv(a) for (int& x: a) cin >> x;
#define llv(a) for (ll& x: a) cin >> x;
#define pri(a) for (int& x: a) cout << x << ' '
int const MOD = 998244353;
int const lg = 20;
int const block = 500;
// int block;
int const MAX = 1e3 + 1, N = 20;
int n, m, q, k, p;
int a[25][25];
void bexuyen67() {
      cin >> n;
      vector<int> a(n);
      inv(a)
      cin >> m;
      vector<int> b(m);
      inv(b)
      vector<pii> scores;
      for (int x: a){
            scores.emplace_back(x, 0);
      }
      for (int x: b){
            scores.emplace_back(x, 1);
      }
      int fh = 0, tur = 0;
      sort(all(scores));
      int cnta = 0, cntb = 0;
      int pre = -1;
      for (auto [score, type]: scores){
            if (type){
                  cntb++;
            }
            else cnta++;
            if (cnta > cntb){
                  if (pre == 1){
                        tur++;
                  }
                  pre = 0;
            }
            else if (cntb > cnta){
                  if (pre == 0){
                        tur++;
                  }
                  pre = 1;
            }
            if (score <= 1440)
                  fh++;
      }
      cout << fh << '\n' << tur;
}

signed main() {
#ifdef binhball
      freopen("input.txt", "r", stdin);
      freopen("output.txt", "w", stdout);
#endif
      cin.tie(0)->sync_with_stdio(0);
      cout << fixed << setprecision(15);
      int t = 1;
      // cin >> t;
      while (t--)
            bexuyen67();
}

• Subtask 1: 50 / 50