Submission #878564

#	Time	Username	Problem	Language	Result	Execution time	Memory
878564		cnn008	Type Printer (IOI08_printer)	C++14	10 / 100	23 ms	25684 KiB

printer

#include "bits/stdc++.h"
using namespace std;
#define int long long
#define cebug(x) cerr << "[" << #x << "] = " << x << endl

const int N=5e4+5;
const int mod=1e9+7;

int n,res;
struct Trie{
	struct Node{
		int child[26];
		int end;
	}node[N];
	void init(){
		for(int i=0; i<N; i++) memset(node[i].child,-1,sizeof(node[i].child));
		for(int i=0; i<N; i++) node[i].end=0;
	}
	int nx=1;
	void insert(string s){
		int v=0;
		for(auto c:s){
			if(node[v].child[c-'a']==-1) node[v].child[c-'a']=nx++;
			v=node[v].child[c-'a'];
		}
		node[v].end=1;
	}
};
Trie trie;
string ans,ss,s[N];
int pos,cnt2[26];
bool cmp(string a, string b){
	return (int)a.size()<(int)b.size();
}
void dfs(int v){
	if(trie.node[v].end){
		for(auto zz:ss){
			int i=zz-'a';
			if(trie.node[v].child[i]!=-1){
				dfs(trie.node[v].child[i]);
				ans.push_back('-');
			}
		}
		ans.push_back('P');
		return;
	}
	for(auto zz:ss){
		int i=zz-'a';
		if(trie.node[v].child[i]!=-1){
			ans.push_back(zz);
			dfs(trie.node[v].child[i]);
			ans.push_back('-');
		}
	}
}
void sol(){
	trie.init();
	cin>>n;
	for(int i=1; i<=n; i++) cin>>s[i];
	sort(s+1,s+n+1,cmp);
	for(int i=1; i<=n; i++){
		for(int j=0; j<(int)s[i].size(); j++){
			if(!cnt2[s[i][j]-'a']){
				ss.push_back(s[i][j]);
				cnt2[s[i][j]-'a']=1;
			}
		}
	}
	for(int i=1; i<=n; i++) trie.insert(s[i]);
	dfs(0);
	for(int i=(int)ans.size()-1; i>=0; i--){
		if(ans[i]=='P'){
			pos=i;
			break;
		}
	}
	cout<<pos+1<<endl;
	for(int i=0; i<=pos; i++) cout<<ans[i]<<"\n";
}
signed main(){
	ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    //freopen(".inp", "r", stdin);
    //freopen(".out", "w", stdout);
    int t=1;
    //cin>>t; 
    while(t--){
    	sol();
    }
    cerr << "\nTime elapsed: " << 1000.0 * clock() / CLOCKS_PER_SEC << " ms.\n";
    return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10