# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
875252 | vjudge1 | Necklace (Subtask 4) (BOI19_necklace4) | C++17 | 281 ms | 572 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define foru(i, l, r) for(int i=(l); i<=(r); ++i)
#define ford(i, l, r) for(int i=(l); i>=(r); --i)
#define fore(x, v) for(auto &x : v)
#define all(x) (x).begin(), (x).end()
#define sz(x) (int)(x).size()
const int N = 6006;
int n, m, kmp1[N], kmp2[N];
tuple<int, int, int> ans;
string s, t, t2;
void calc(string s, int *kmp) {
kmp[sz(s)] = 0;
foru(i, 1, sz(s)-1) {
int j = kmp[i-1];
while (j > 0 && s[j] != s[i]) j = kmp[j-1];
if (s[j] == s[i]) j += 1;
kmp[i] = j;
}
}
tuple<int, int, int> solve(bool rev) {
tuple<int, int, int> ret = {0, 0, 0};
foru(i, 0, n) {
string suf = s.substr(i, n-i), pre = s.substr(0, i);
reverse(all(pre));
calc(suf + '#' + t, kmp1); calc(pre + '#' + t2, kmp2);
foru(j, 0, m) ret = max(ret, {
kmp1[n-i+j]+kmp2[i+m-j],
i - kmp2[i+m-j],
j - kmp1[n-i+j]
});
}
if (rev) {
get<1>(ret) = n-get<1>(ret)-1-get<0>(ret)+1;
}
return ret;
}
int main() {
cin >> s >> t;
n = sz(s); m = sz(t);
t2 = t;
reverse(all(t2));
ans = solve(0);
reverse(all(s));
ans = max(ans, solve(1));
cout << get<0>(ans) << "\n" << get<1>(ans) << " " << get<2>(ans);
}
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